PHP的數據庫查詢

Question

我有企業目錄網站，我希望它可以像Craigslist一樣將所有帖子分組。

目前我的數據會出現在網站上這樣

<business name1> <phone number> <jan 13 2012> 
<business name2> <phone number> <jan 13 2012> 
<business name1> <phone number> <jan 12 2012> 

我想佈局像這樣，這樣的職位將由日期組發佈。

<jan 13 2012> 
<business name1> <phone number> 
<business name2> <phone number> 

<jan 12 2012> 
<business name1> <phone number> 
<business name2> <phone number> 

這裏是我的編碼

connection 
$query = "SELECT * FROM `myname` ORDER BY `myname`.`id` DESC LIMIT $offset, $limit "; 
$result = mysql_query($query); 


    while($row = mysql_fetch_row($result)) 

    { 

?> 

<div class="list"> 
<div class="ads_name"><a href="http://www.mydomain.com/category/<?=$row[0]?>.html" target="_blank"><?=$row[4]?> </a></div> 
    <div class="location"><?= htmlspecialchars($row[5])?></div> 
    <div class="phone"><?=formatPhoneNumber($row[3])?></div> 
    <div class="date"><?=$row[9]?></div> 
</div> 

<?php 
    } 
    mysql_free_result($result); 
?> 

Answer 1

首先，你需要像

SELECT * FROM `myname` ORDER BY `myname`.`mydate` DESC, `myname`.`id` DESC LIMIT $offset, $limit 

爲了確保您的行以正確的順序到達。接下來，您需要執行經典的組更改算法：

<?php 
... 

    $date='__invalid__'; 
    while($row = mysql_fetch_row($result)) 

    { 

     if ($row[9]!=$date) 
     { 
     $date=$row[9]; 
?> 
<div class="date_header"><?=$row[9]?></div> 

<?php 
     } 
?> 

<div class="list"> 
<div class="ads_name"><a href="http://www.mydomain.com/category/<?=$row[0]?>.html" target="_blank"><?=$row[4]?> </a></div> 
    <div class="location"><?= htmlspecialchars($row[5])?></div> 
    <div class="phone"><?=formatPhoneNumber($row[3])?></div> 
    <div class="date"><?=$row[9]?></div> 
</div> 

<?php 
    } 
    mysql_free_result($result); 
?>