MySQL查詢聯接QUERY2

Question

我有以下MySQL查詢：

SELECT * 
FROM quizquestions 
INNER JOIN option2 ON quizquestions.question_id=option2.question_id 
WHERE quizquestions.quiz_id=13 

基本上，我有兩個表，一個表有問題，另一個表存儲4個選項的每一個問題。因此，例如，在quizquestions表將如下所示：使用循環同時顯示問題和選項

Option id (Primary Key), Question_id(To link it to the correct question), optionvalue 

     181    61            3 

目前，即時通訊：

Question_id (Primary Key), quiz_id(to link it to the quiz), question 

    61      13        1+2 

然後選擇表會像下面然而，每當我使用INNER JOIN查詢如上述所示，I得到以下：

question_id quiz_id question optionid question_id optionvalue 

    61   13  1+2  181   61   1 
    61   13  1+2  182   61   2 
    61   13  1+2  183   61   3 
    61   13  1+2  184   61   4 

然而，我想它顯示這樣的：

Question_id Quiz_ID  question optionvalue optionvalue optionvalue optionvalue 

    61   13   1+2  1    2   3    4 

這是這樣，我不會有第一列中看到question_id/quiz_id的重複。

這可以實現嗎？

Answer 1

SELECT q.Question_id as questionId, q.Quiz_ID as quizId, q.question as question, GROUP_CONCAT(op.optionvalue SEPARATOR ' ') as options 
FROM quizquestions q INNER JOIN option2 op ON q.question_id=op.question_id WHERE q.quiz_id=13 
GROUP BY q.Question_id 

OR

SELECT q.Question_id as questionId, q.Quiz_ID as quizId, q.question as question, 
SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(op.optionvalue), ',', 1), ',', -1) AS option1, 
SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(op.optionvalue), ',', 2), ',', -1) AS option2, 
SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(op.optionvalue), ',', 3), ',', -1) AS option3, 
SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(op.optionvalue), ',', 4), ',', -1) AS option4 
    FROM quizquestions q INNER JOIN option2 op ON q.question_id=op.question_id WHERE q.quiz_id=13 
    GROUP BY q.Question_id 

試試這個。