如何從兩列逐日獲得總延遲？

我有命名爲互聯網與3列一個MySQL數據庫中的表：ID，dropped_at和dropped_to如圖這一形象如何從兩列逐日獲得總延遲？

如何通過日期找到總延遲組？

好了，我已經試過，但它不能正常在這裏工作是我的MySQL代碼：

SELECT 
    dropped_at, 
    dropped_to, 
    TIMEDIFF(dropped_to,dropped_at) AS delay 
FROM 
    internet 
WHERE 
    WEEKDAY(dropped_at) BETWEEN 0 AND 6 AND 
    WEEK (dropped_at) = WEEK (NOW()) 
GROUP BY CAST(dropped_to AS DATE)

來源

2016-08-24 Suraj Kumar

你嘗試過這麼遠嗎？顯示你至少嘗試了一些東西，並隨時分享。 **提示：** SUM（TIMESTAMPDIFF（MINUTE，dropped_at，dropped_to））＆GROUP BY DATE（dropped_at）' – 1000111

請提供創建表並插入表查詢， – Naruto

如果你想每天總的延遲，則下面的查詢會工作：

SELECT 
DATE(dropped_at) AS date, 
SUM(TIMESTAMPDIFF(MINUTE,dropped_at,dropped_to)) AS delayInMinutes 
FROM internet 
GROUP BY date 
ORDER BY date;

備註：延遲時間爲MINUTES。只要你喜歡

你可以把它改成任何單位如果你想在hh:mm:ss格式延遲請嘗試以下查詢，而不是

SELECT 
DATE(dropped_at) AS date, 
SEC_TO_TIME(SUM(TIMESTAMPDIFF(SECOND,dropped_at,dropped_to))) AS delay 
FROM internet 
GROUP BY date 
ORDER BY date;

來源

2016-08-24 05:05:02 1000111

如何從兩列逐日獲得總延遲？

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