的Python：轉換JSON（通過URL返回）到列表

Question

我請求與jQuery的自動完成功能使用YouTube的搜索詞，但我有一個很難轉換的URL響應轉換爲正確的格式。

在我（Django的/ Python）的觀點我做的：

data2 = urllib2.urlopen('http://suggestqueries.google.com/complete/search?hl=en&ds=yt&client=youtube&hjson=t&jsonp=window.yt.www.suggest.handleResponse&q=jum&cp=3') 

（我硬編碼搜索項=爲簡單起見， '跳'）

如果我做data2.read()我得到了我認爲是JSON （複製粘貼網址到瀏覽器也會返回此。）

window.yt.www.suggest.handleResponse(["jum",[["jumpstyle","","0"],["jump","","1"],["jump around","","2"],["jump on it","","3"],["jumper","","4"],["jump around house of pain","","5"],["jumper third eye blind","","6"],["jumbafund","","7"],["jump then fall taylor swift","","8"],["jumpstyle music","","9"]],"","","","","",{}]) 

我需要在jQuery的自動完成功能可以讀取的格式返回此。我知道它會工作，如果我能得到它到一個列表，例如，mylist = ['jumpstyle', 'jump', 'jump around', ...]

然後將其轉換回JSON返回之前：

json.dumps(mylist) 

（這工作，如果我直接直接定義mylist爲）

但我無法從URL返回的數據傳遞給一個簡單的列表（然後我轉換回JSON）或某種形式的JSON，我可以直接返回被使用自動完成。

我試過，除其他事項外，

j2 = json.loads(data2) 

和

j2 = json.loads(data2.read()) 

希望有人能幫助！

Answer 1

刪除&jsonp=window.yt.www.suggest.handleResponse部分

import json 
import urllib2 

data = urllib2.urlopen('http://suggestqueries.google.com/complete/search?hl=en&ds=yt&client=youtube&hjson=t&q=jum&cp=3') 

j = json.load(data) 
k = [i for i, j, k in j[1]] 
l = json.dumps(k) 

Answer 2

它不是JSON它的JavaScript，如果你想用它作爲JSON你必須剝去的JavaScript部分：

j2 = json.loads(data2[37:-1]) 

，但你可以改變的URL（去掉「JSONP = window.yt.www .suggest.handleResponse」部分）具有純JSON輸出：

>>> data2 = urllib2.urlopen('http://suggestqueries.google.com/complete/search?hl=en&ds=yt&client=youtube&hjson=t&q=jum&cp=3') 
>>> json.loads(data2.read()) 
[u'jum', [[u'jumpstyle', '', u'0'], [u'jump', '', u'1'], [u'jump around', '', u'2'], [u'jump on it', '', u'3'], [u'jumper', '', u'4'], [u'jump around house of pain', '', u'5'], [u'jumper third eye blind', '', u'6'], [u'jumbafund', '', u'7'], [u'jump then fall taylor swift', '', u'8'], [u'jumpstyle music', '', u'9']], '', '', '', '', '', {}] 

Answer 3

從頁的輸出是不正確的JSON編碼數據。您需要刪除的JS函數調用加以包裝。

做到這一點：

import urllib2 
import re 
import json 

data2 = urllib2.urlopen('http://suggestqueries.google.com/complete/search?' +  
    'hl=en&ds=yt&client=youtube&hjson=t&jsonp=window.yt.' + 
    'www.suggest.handleResponse&q=jum&cp=3') 

data = re.compile('^[^\(]+\(|\)$').sub('', data2.read()) 
parsedData = json.loads(data) 

parsedData是蟒蛇陣了。

Answer 4

你正在做自動包裝了JSON在JavaScript回調函數JSON-P請求時，你已經在事實上請求:)

地帶遠離你的請求和JSON-P參數指定的一個你將直接獲得直接從JSON的要求，而無需做任何額外的東西蟒在所有。

這應該是你的要求：

http://suggestqueries.google.com/complete/search?hl=en&ds=yt&client=youtube&hjson=t&q=jum&cp=3 

，它將返回：

["jum",[["jumpstyle","","0"],["jump","","1"],["jump around","","2"],["jump on it","","3"],["jumper","","4"],["jump around house of pain","","5"],["jumper third eye blind","","6"],["jumbafund","","7"],["jump then fall taylor swift","","8"],["jumpstyle music","","9"]],"","","","","",{}]