Dataweave：獲取，而不是字符串

Question

com.mulesoft.weave.model.structure.QualifiedName我有一個數據庫查詢，像這樣返回數據：

"LABEL","CONTAINER_ID","STATUS" 
"14.JW24","1006063116","F" 
"14.JW25","1006063116","F" 
"1.JW2M","9999997","R" 
"8.282","9999999","R" 
"4.135","9999999","F" 
"6.43","9999999","F" 
"11.12","9999999","R" 
"14.JW12","1006063073","R" 
"14.JW13","1006063073","R" 
"14.JW10","1006063068","F" 

我使用Dataweave創建不同的列表具有「F」狀態的container_id值。喜歡的東西：

["1006063116", "9999999", "1006063068"] 

這裏是我的dataweave腳本：

%dw 1.0 
%output application/java 
--- 
payload filter $.STATUS == "F" groupBy $.CONTAINER_ID pluck $$ 

，我得到com.mulesoft.weave.model.structure.QualifiedName對象的列表，而不是名單這工作，除了罰款字符串。

我該如何修改dataweave腳本才能獲取字符串，或者，如何從QualifiedName對象獲取字符串值？我試過在對象上調用toString（）和getName（）。前者不給我需要的價值，後者不起作用。

Answer 1

只投，結果元素串這樣的：

%dw 1.0 
%output application/java 
--- 
payload filter $.STATUS == "F" groupBy $.CONTAINER_ID pluck $$ as :string 

的重要組成部分，是as :string

替代解決方案：您可以使用distinctBy關鍵字來實現類似的結果，並擺脫GROUPBY +勇氣的：

%dw 1.0 
%output application/java 
--- 
(payload filter $.status == "F").container_id distinctBy $