閱讀數據文件和幫助更正程序

Question

我被賦予一個計算火箭開始下落的時間，並賦值給一個名爲rocket1.txt的文件這是我第一次做一個程序，我們需要從這裏讀取信息另一個文件。這是我迄今爲止，如果任何人都可以幫助我糾正這是偉大的。

#include<stdio.h> 
    #define FILENAME "rocket1.txt" 
    int main(void) 
    { 
     /*Declare variables*/ 
     errno_t err; 
     int number_of_pts, k; 
     double rocket_acc, new_alt = 0; 
     double old_alt = 0.0, old_time, new_time, rocket_vel; 
     FILE *rocket1; 

     /*Open File*/ 
     err = fopen_s(&rocket1, "rocket1.txt", "r"); 
     if (err) 
      printf("Problem opening file. \n"); 
     else 
     { 
      while ((number_of_pts > 0) && (new_alt >= old_alt)); 
      { 
       old_alt = new_alt; 
       old_time = new_time; 
       fscanf(rocket1, "%lf%lf%lf%lf", &new_time, &new_alt, &rocket_acc, &rocket_vel); 

      } 
      if (new_alt < old_alt) 
       printf("The rocket begins to fall. \n") 
       printf("%4.2f seconds and %4.2f seconds", old_time, new_time); 

      else 
      { 

       printf("There is no Decrease in Altitude. \n"); 
      } 

     } 

     getchar(); 
      return 0; 
    } 

我得到一個錯誤的非法使用，如果else語句（這是用我的第一次，這些爲好，林不知道，如果循環是對這類問題的正確。附加的文件給出了

24 
    1.0000000e+01 2.9265380e+03 5.0821200e+02 4.3231640e+01 
    2.0000000e+01 1.0170240e+04 9.2798610e+02 4.0723180e+01 
    3.0000000e+01 2.1486260e+04 1.1832420e+03 1.0328000e+01 
    4.0000000e+01 3.3835080e+04 1.1882285e+03 -9.3307000e+00 
    5.0000000e+01 4.5250830e+04 1.0899705e+03 -1.0320900e+01 
    6.0000000e+01 5.5634490e+04 9.8935650e+02 -9.8019000e+00 
    7.0000000e+01 6.5037960e+04 8.9134700e+02 -9.8000000e+00 
    8.0000000e+01 7.3461430e+04 7.9334750e+02 -9.7999000e+00 
    9.0000000e+01 8.0904910e+04 6.9534750e+02 -9.8001000e+00 
    1.0000000e+02 8.7368380e+04 5.9734700e+02 -9.8000000e+00 
    1.1000000e+02 9.2851850e+04 4.9934700e+02 -9.8000000e+00 
    1.2000000e+02 9.7355320e+04 4.0134750e+02 -9.7999000e+00 
    1.3000000e+02 1.0087880e+05 3.0334400e+02 -9.8008000e+00 
    1.4000000e+02 1.0342220e+05 2.0534500e+02 -9.7990000e+00 
    1.5000000e+02 1.0498570e+05 1.3402000e+02 -4.4660000e+00 
    1.6000000e+02 1.0610260e+05 2.6304000e+02 3.0270000e+01 
    1.7000000e+02 1.1024650e+05 6.7618500e+02 5.2359000e+01 
    1.8000000e+02 1.1962630e+05 1.2929950e+03 7.1003000e+01 
    1.9000000e+02 1.3610640e+05 2.1234700e+03 9.5092000e+01 
    2.0000000e+02 1.6209570e+05 3.1700000e+03 1.1421400e+02 
    2.1000000e+02 1.9950640e+05 3.8340050e+03 1.8587000e+01 
    2.2000000e+02 2.3877580e+05 3.8779450e+03 -9.7990000e+00 
    2.3000000e+02 2.7706530e+05 3.7799500e+03 -9.8000000e+00 
    2.4000000e+02 3.1437480e+05 3.6819500e+03 -9.8000000e+00 

Answer 1

你已經錯過了在下面的代碼片段括號和分號

if (new_alt < old_alt) 
{ /* HERE*/ 
     printf("The rocket begins to fall. \n") ; /* HERE*/ 
     printf("%4.2f seconds and %4.2f seconds", old_time, new_time); 
} /* HERE*/ 
else 
{ 
     printf("There is no Decrease in Altitude. \n"); 
}