從谷歌日曆返回json和用php解析

Question

$current = $_GET['current']; 
$future = $_GET['future']; 
//$CMD = $_GET['CMD']; 

$current = mktime(0,0,0,date("m"),date("d"),date("Y")); 
$currentDate = date("Y-m-d",$current); 

$future = mktime(0,0,0,date("m"),date("d")+7,date("Y")); 
$futureDate = date("Y-m-d", $future); 
//need to get the futureDate for URL 
//$futrureDate = date("Y-m-d",$_GET['finalDate']) 

// build feed URL 
$googleURL = "http://www.google.com/calendar/feeds/$userid/private-$magicWord/basic?start-min=$currentDate&start-max=$futureDate/full?alt=json"; 
//$googleURL = "http://www.google.com/calendar/feeds/$userid/private-$magicWord/basic?alt=json"; 
//$url = "http://www.google.com/calendar/feeds/developer-calendar@google.com/public/full?alt=json"; 
$data = file_get_contents($googleURL); 
echo $data; 
//$json = json_encode($data); 
//echo $json; 
//By default json_decode returns an stdClass object. You have to give a second parameter for this function TRUE. 
$object = json_decode($json,TRUE); 
print_r($object->title[1]); 

//echo $object->title[0]; 

我在哪裏把日期變量中的alt = json放在url中。它可以正常工作，當我從URL中排除日期，但隨後對它們無效。也當我嘗試打印一個特定的對象時，我得到一個錯誤，該對象不存在。謝謝！

Answer 1

嘗試 -

$googleURL = "http://www.google.com/calendar/feeds/$userid/private-$magicWord/basic?start-min=$currentDate&start-max=$futureDate/full&alt=json"; 

Answer 2

它出現的URL方案要求一個基本觀點，然後添加完整視圖。 （您只能有一個。）

嘗試之一：

$googleURL = "http://www.google.com/calendar/feeds/$userid/private-$magicWord/basic?start-min=$currentDate&start-max=$futureDate&alt=json"; 

或

$googleURL = "http://www.google.com/calendar/feeds/$userid/private-$magicWord/full?start-min=$currentDate&start-max=$futureDate&alt=json";