Java進行陳述和掃描儀輸入

Question

 System.out.println ("Did you see that?"); 
     String response = input2.nextLine(); 
     System.out.println ("You said "+ response);  

     String[] responses = {"no", "NO", "No", "I did not"}; 

     List<String> response1 = Arrays.asList (responses); 

     for (String response : response1 ){ 
      System.out.println ("That was weird"); 
     } 

我是新來的Java，並想知道我怎麼會在某種程度上使用「爲」聲明說，當你輸入的詞語，如「不」的列表中的一個， 「否」或「否」，會有一些涵蓋這些輸入的迴應。我只是想減少if和else語句的數量。

Answer 1

代碼中的問題是，您對用戶輸入和循環變量都使用相同的變量 - response。更改循環變量：

for (String noResponse : responses ){ 
     if (response.equals(noResponse)) { // you can also use .contains if you 
              // don't require an exact match 
      System.out.println("You said no"); 
      break; 
     } 
    } 

BTW，沒有必要到responses數組轉換成List。循環可以遍歷數組。

Answer 2

你可以用列表的方法來檢查它是否包含了response.Like這樣的：

System.out.println ("Did you see that?"); 
    Scanner input2=new Scanner(System.in); 
    String response = input2.nextLine(); 
    System.out.println ("You said "+ response);  

    String[] responses = {"no", "NO", "No", "I did not"}; 

    List<String> response1 = Arrays.asList (responses); 

    if(response1.contains(response)){ 
     System.out.println ("That was weird"); 
    } 

Answer 3

作爲一個額外的音符，而不是使可能的響應數組，你可能想要做類似的東西這樣的：

if(response.equalsIgnoreCase("no") || response.equalsIgnoreCase("I did not")){ 
    System.out.println("that was weird"); 
} 

這將檢查「否」或「我沒有」，而是忽略的情況下，所以你不必擔心。