使用來自多個陣列的屬性對模型進行分頁

Question

我有四種類型的Rawscores，我想在分頁表中一起顯示。

代碼如下：

@facebook_scores_today = Rawscore.where(:channel_string => "Facebook", :project => @project, :created_at.gt => Time.now.beginning_of_day) 

@youtube_scores_today = Rawscore.where(:channel_string => "Youtube", :project => @project, :created_at.gt => Time.now.beginning_of_day) 

@twitter_scores_today = Rawscore.where(:channel_string => "Twitter", :project => @project, :created_at.gt => Time.now.beginning_of_day) 

@influence_scores_today = Rawscore.where(:channel_string => "Influence", :project => @project, :created_at.gt => Time.now.beginning_of_day) 

凡Rawscore有多個值atributes爲根據:channel_string表中的哈希值。

我應該怎麼辦？任何寶石可以幫助「will_paginate」或「kaminari」？

更新（這是我的Rawscore模型）

class Rawscore 
    include Mongoid::Document 
    include Mongoid::Timestamps::Created #for created_at field 

    belongs_to :channel 
    belongs_to :project 
    field :values, type: Hash 
    validates :values, :presence => true 

end 

我想以顯示鍵值：在Rawscore模型值散列。

Answer 1

的問題的答案在於採用WillPaginate ::收集來創建自己的分頁結構分頁。

這裏是rubydoc鏈接：http://rubydoc.info/github/mislav/will_paginate/frames

Answer 2

雷可以分頁陣列，但它不是有效的，因爲活動記錄將會被實例化所有檢索的記錄（即，如果你有10000條記錄，並希望只顯示100，會出現內存10000個AR對象）

Kaminari.paginate_array(my_array_object).page(params[:page]).per(10) 

相反，你可以考慮加入你的查詢和使用查詢

scores_today = Rawscore.where(
    :channel_string => ["Facebook", "Youtube", "Twitter", "Influence"], 
    :project => @project, :created_at.gt => Time.now.beginning_of_day 
).page(params[:page])