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我花了一些代碼,這應該是工作和看到的desinged它不工作,我 坦率地掙扎着爬什麼是錯的,我需要填寫的所有籃筐,但現在只有第一次得到填補,我是否需要做任何支點?或通過選擇擺脫更新? Id'like有相同的5行的Tx,並填寫所有籃ALL TxID添加,這個自含以下例子可以說明這一點:與TSQL更新選擇加入的問題
SELECT * INTO #lkup FROM ( -- drop table #lkup -- select * from #lkup
SELECT 201 Cust_ID, 1 Line, 'Pr1' ProductID UNION
SELECT 201 Cust_ID, 2 Line, 'Pr20' ProductID UNION
SELECT 201 Cust_ID, 3 Line, 'Pr333' ProductID ) g
SELECT * INTO #tx FROM ( -- drop table #tx -- select * from #tx
SELECT 201 Cust_ID, cast (NULL AS varchar(7)) Prod1, cast (NULL AS varchar(7)) Prod2, cast (NULL AS varchar(7)) Prod3 , 12001 TxID UNION
SELECT 201 Cust_ID, cast (NULL AS varchar(7)) Prod1, cast (NULL AS varchar(7)) Prod2, cast (NULL AS varchar(7)) Prod3 , 12002 TxID UNION
SELECT 201 Cust_ID, cast (NULL AS varchar(7)) Prod1, cast (NULL AS varchar(7)) Prod2, cast (NULL AS varchar(7)) Prod3 , 12003 TxID UNION
SELECT 201 Cust_ID, cast (NULL AS varchar(7)) Prod1, cast (NULL AS varchar(7)) Prod2, cast (NULL AS varchar(7)) Prod3 , 12004 TxID UNION
SELECT 201 Cust_ID, cast (NULL AS varchar(7)) Prod1, cast (NULL AS varchar(7)) Prod2, cast (NULL AS varchar(7)) Prod3 , 12005 TxID ) g
UPDATE tx
SET Prod1 = CASE WHEN LINE =1 THEN ProductID END,
Prod2 = CASE WHEN LINE =2 THEN ProductID END,
Prod3 = CASE WHEN LINE =3 THEN ProductID END
--- SELECT l.Line, l.ProductID, tx.*
FROM #tx tx
JOIN #lkup l ON l.Cust_ID = tx.Cust_ID
SELECT * FROM #tx -- update #tx set Prod1 = ' ', Prod2 = ' ', Prod3 = ' '
SELECT 'Shouldbe' , '201' CustID, 'Pr1' Prod1, 'Pr20' Prod1, 'Pr333' Prod1, 12001 TxID -- for each Tx 5 rows Total
引人入勝。它可能是未定義的(或不確定的)行爲。嘗試用'RIGHT JOIN'替換更新語句的'JOIN',看看會發生什麼。你可以用子查詢重寫'CASE'東西到'#lkup'嗎? – dlatikay
Tx我嘗試使用(選擇)括號而不是案例,它並沒有採取它,可能b'z UPDATE語法。與RIGHT JOIN它現在捕獲Prod1和Prod3,但仍然不是Prod2(?)。 –
更正:這實際上有效,但將是我最後的手段,我也有人y籃子,並在真正的設置我嵌套選擇JOIN。 UPDATE #tx SET#tx.Prod1 = –