MySQL的ORDER BY XY/X ASC

Question

我要訂購此規則上升MySQL查詢：x-y/x

X =價格

Y = price2

價格和price2是從MySQL中的列表。

我有這個查詢，但不幸的是沒有工作。

SELECT * 
FROM albums 
WHERE price2 > 1 
ORDER BY price - price2/price ASC 

感謝您的關注。

Answer 1

嘗試了這一點：

$SQLquery = "SELECT * FROM albums WHERE price2 > 1 ORDER BY (price-price2)/price ASC"; 

或

$SQLquery = "SELECT * FROM albums WHERE price2 > 1 ORDER BY ((price-price2)/price) ASC"; 

Answer 2

你應該嘗試：

SELECT * FROM albums 
WHERE price2 > 1 
ORDER BY ((price - price2)/price) ASC 

或

SELECT albums.*, ((price - price2)/price) myvar FROM albums 
WHERE price2 > 1 
ORDER BY myvar ASC 

Answer 3

順序按基於指定列的作品。您可以從基表中創建一個視圖或臨時表，其中包含一個具有基於該公式的值的新列，然後對該列進行排序。