茉莉花 - 兩個間諜的方法相同

Question

我是Jasmine的新手，我想知道我們是否可以爲同一個方法創建2個間諜。這是我正在嘗試的。

describe('something', function() { 
    beforeEach(function() { 
     mySpy = jasmine.createSpyObj('mySpy', 'functionInInterest'); 
     mySpy.functionInInterest.andCallFake(function (cb) {cb(something);}); 
    } 

    //Some Test Cases 
    describe('Here is the action!', function() { 
     mySpy = jasmine.createSpyObj('mySpy', 'functionInInterest'); 
     mySpy.functionInInterest.andCallFake(function (cb) {cb(somethingElse);}); 
     //Some test cases that depends on somethingElse 
    }); 
}); 

測試用例Here is the action!取決於mySpy.functionInInterest.andCallFake(function (cb) {cb(something);});其中作爲測試用例之前內部Here is the action!取決於mySpy.functionInInterest.andCallFake(function (cb) {cb(somethingElse);});

注：兩個具有相同的名稱

我怎樣才能做到這一點？提前致謝！

Answer 1

代替

describe('Here is the action!', function() { 
     mySpy = jasmine.createSpyObj('mySpy', 'functionInInterest'); 
     mySpy.functionInInterest.andCallFake(function (cb) {cb(somethingElse);}); 
     //Some test cases that depends on somethingElse 
    }); 

做到這一點

describe('Here is the action!', function() { 
     mySpy_2 = jasmine.createSpyObj('mySpy', 'functionInInterest'); 
     mySpy_2.functionInInterest.andCallFake(function (cb) {cb(somethingElse);}); 
     //Some test cases that depends on somethingElse 
    });