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我正在使用Jackson將json字符串解析爲scala案例類實例。 這裏是我的代碼遞歸類型轉換jackson json解析器
import com.fasterxml.jackson.databind.{DeserializationFeature, ObjectMapper}
import com.fasterxml.jackson.module.scala.DefaultScalaModule
import scala.reflect.{ClassTag, _}
object JsonUtil {
val jacksonMapper = new ObjectMapper()
jacksonMapper.registerModule(DefaultScalaModule)
jacksonMapper.configure(DeserializationFeature.FAIL_ON_MISSING_CREATOR_PROPERTIES, false)
jacksonMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false)
def toJson(value: Map[Symbol, Any]): String = {
toJson(value map { case (k,v) => k.name -> v})
}
def toJson(value: Any): String = {
jacksonMapper.writeValueAsString(value)
}
def fromJson[T: ClassTag](json: String): T = {
jacksonMapper.readValue[T](json, classTag[T].runtimeClass.asInstanceOf[Class[T]])
}
}
,這是該JSON解析錯誤
case class Person(name: String, age: Long, score: List[Long])
val person = JsonUtil.fromJson[Person]("""{"name": 123654,"age":23, "score": [6,7,9]}""")
person.name
person.score
person.score.head
res0: String = 123654
java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.Long
at scala.runtime.BoxesRunTime.unboxToLong(ws.sc93376:101)
at #worksheet#.#worksheet#(ws.sc93376:35)
我知道傑克遜是足夠聰明的數字類型,字符串,數字,反之亦然之間進行轉換,但似乎只適用於非收集情況。
我怎麼能做得更好,力量傑克遜遞歸轉換內部集合類型?