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我是一個C++初學者,我正在嘗試定義一個BubbleSort函數來對鏈表中的元素進行排序。C++ BubbleSort LinkedList
//define Node in class List
//Node.h
template<typename T> class List;
template<typename T>
class Node{
friend class List<T>;
public:
Node(T &); //constructor
T getData() const; //access data
private:
T data;
Node<T> *nextPtr; //point to the next Node
};
template<typename T>
Node<T> ::Node(T &key):data(key),nextPtr(0){}
template<typename T>
T Node<T>::getData()const{
return data;
}
//clase List
//List.h
#include<iostream>
#include"Node.h"
using namespace std;
template <typename T>
class List{
public:
List();
void insertAtFront(T);
void insertAtBack(T &);
bool removeFromFront(T &);
bool removeFromBack(T &);
bool isEmpty() const;
void print() const;
void BubbleSort();
private:
Node<T> *firstPtr;
Node<T> *lastPtr;
Node<T> *getNewNode(T&);
};
template<typename T>
List<T> :: List():firstPtr(0),lastPtr(0){}
template<typename T>
void List<T>::BubbleSort(){
Node<T> *current; //Point to the current node
Node<T> *temp = firstPtr; //hold the data of first element
for(bool swap = true; swap;){ // if no swap occurs, list is in order
swap =false;
for(current = firstPtr ; current != 0 ; current= current ->nextPtr){
if (current->data > current->nextPtr->data){ //swap data
temp->data = current->data;
current->data = current->nextPtr->data;
current->nextPtr->data = temp ->data;
swap = true;
}
}
}
}
你們能不能幫我解決這個問題: 但在
for(current = firstPtr ; current != 0 ; current= current ->nextPtr)
說
First-chance exception at 0x01375557 in 111.exe: 0xC0000005: Access violation reading location 0x00000000.
Unhandled exception at 0x01375557 in 111.exe: 0xC0000005: Access violation reading location 0x00000000.
這裏是核心代碼中出現錯誤? 我用調試,但仍然找不到解決方案。 謝謝。
我認爲這是目前'=電流 - > nextPtr'所引發錯誤。不確定。爲什麼不在函數的開頭檢查'firstPtr'是否爲'0'? – Shoe 2013-03-17 04:59:22