直接用電子郵件聯繫表格，使用php

Question

我嘗試了很多方法來解決這個問題，但好像我碰到了牆壁。它應該與這種方式的工作，但我無法找到任何錯誤，因爲這是寫有一個

語法錯誤，意想不到的$結束

後我點擊提交按鈕。

首先，我輸入這樣的代碼。

<form class="form" method="post" action="sendContact.php"> 
       <table> 
        <tr> 
         <td class="contact-firstcol"> <label for="name">Name</label> </td> 
         <td class="contact-secondcol"> : </td> 
         <td class="contact-thirdcol"> <input type="text" name="name" id="name" /> </td> 
        </tr> 
        <tr> 
         <td class="contact-firstcol"> <label for="email">Email</label> </td> 
         <td class="contact-secondcol"> : </td> 
         <td class="contact-thirdcol"> <input type="text" name="email" id="email" /> </td> 
        </tr> 
        <tr> 
         <td class="contact-firstcol"> <label for="phone">Phone</label> </td> 
         <td class="contact-secondcol"> : </td> 
         <td class="contact-thirdcol"> <input type="text" name="phone" id="phone" /> </td> 
        </tr> 
        <tr> 
         <td class="contact-firstcol"> <label for="message">Message</label> </td> 
         <td class="contact-secondcol"> : </td> 
         <td class="contact-thirdcol"> <textarea id="message" name="message"></textarea> </td> 
        </tr> 
        <tr> 
         <td class="contact-firstcol"></td> 
         <td class="contact-secondcol"></td> 
         <td class="contact-thirdcol"> <input type="submit" name="submit" value="SUBMIT" /> </td> 
       </table>  
      </form> 

該文件名爲sendContact.php

  <?php 
      $to = 'abc@abc.com'; 
      $subject = 'from email contact'; 

      $name = $_POST ['name']; 
      $email = $_POST ['email']; 
      $phone = $_POST ['phone']; 
      $message = $_POST ['message']; 

      $body = <<< EMAIL 
      Hi! My name is $name 
      $message. 
      From : $name 
      Email : $email 
      Topic : $topic 
      EMAIL; 
      $header = "From: $email"; 

      if (isset($_POST)) { 
       if ($name == '' || $email == '' || $topic == '' || $message = '') { 
        $feedback = 'Please fill in any fields.'; 

       } else { 

       mail($to, $subject, $body, $header); 
       $feedback = 'Thanks for the information, we will get back to you in 24 hours.'; 
       } 
      } 
?> 
<p class="feedback"> <?php echo $feedback ?> </p> 

我已經作出這樣簡單，也確保對電子郵件的細節將在輕鬆閱讀。你能指出上面的錯誤嗎？

乾杯

Answer 1

不能有<<<和EMAIL之間的任何空格<<< EMAIL

它必須是<<<EMAIL（見注瞭解更多信息）

諮詢：

http://www.php.net/manual/en/language.types.string.php#language.types.string.syntax.heredoc

對heredoc

實施例＃1無效示例在參數的更多信息（從手動）

<?php 
class foo { 
    public $bar = <<<EOT 
bar 
    EOT; 
} 
?> 

實施例＃2定界符串引述例如

<?php 
$str = <<<EOD 
Example of string 
spanning multiple lines 
using heredoc syntax. 
EOD; 

/* More complex example, with variables. */ 
class foo 
{ 
    var $foo; 
    var $bar; 

    function foo() 
    { 
     $this->foo = 'Foo'; 
     $this->bar = array('Bar1', 'Bar2', 'Bar3'); 
    } 
} 

$foo = new foo(); 
$name = 'MyName'; 

echo <<<EOT 
My name is "$name". I am printing some $foo->foo. 
Now, I am printing some {$foo->bar[1]}. 
This should print a capital 'A': \x41 
EOT; 
?> 

實施例＃3定界符示例

<?php 
var_dump(array(<<<EOD 
foobar! 
EOD 
)); 
?> 

---

和你的情況：（我測試工作）

我改變$topic到$phone否則它會拋出一個錯誤。

您將需要進一步修改您的PHP以反映適當的更改。

<?php 
$to = 'abc@abc.com'; 
$subject = 'from email contact'; 

$name = $_POST ['name']; 
$email = $_POST ['email']; 
$phone = $_POST ['phone']; 
$message = $_POST ['message']; 

$body = <<<EMAIL 
Hi! My name is $name 
$message. 
From : $name 
Email : $email 
Topic : $topic 
EMAIL; 
$header = "From: $email"; 

if (isset($_POST)) { 
    if ($name == '' || $email == '' || $phone == '' || $message = '') { 
     $feedback = 'Please fill in any fields.'; 

    } else { 

    mail($to, $subject, $body, $header); 
    $feedback = 'Thanks for the information, we will get back to you in 24 hours.'; 
    } 
} 
?> 
<p class="feedback"> <?php echo $feedback ?> </p> 

---

腳註：

而作爲Kostis在評論說--- 「這是一個不能有在前面任何空白結束標記同樣重要的是要認識到。關閉標識符之前的第一個字符必須是由本地操作系統定義的換行符。「

---