顛倒NHibernate查詢的邏輯

Question

我已經使用NHibernate構建了以下查詢，它將爲我提供包含給定頁面（由頁面id引用）的MenuView項目的集合。

// Only retrieve the required properties from Menu object 
ProjectionList menuViewProjections = Projections.ProjectionList() 
    .Add(Projections.Property("ID"), "ID") 
    .Add(Projections.Property("Name"), "Name") 
    .Add(Projections.Property("Description"), "Description"); 

var menus = session.CreateCriteria(typeof(Menu)) 
    // Only menu's that are editable 
    .Add(Restrictions.Eq("IsEditable", true)) 

    // Only project required properties 
    .SetProjection(menuViewProjections) 

    // Only menu's that contain this page (Menu object has IList<Page> property called 'Pages') 
    .CreateCriteria("Pages") 
    // Restrict to menu's containing the pages with an id of the specified value 
    .Add(Restrictions.Eq("ID", pageId)) 

    // Transform results into required, light-weight, view objects 
    .SetResultTransformer(Transformers.AliasToBean(typeof(MenuView))) 
    .List<MenuView>(); 

這工作正常;然而，現在我想做相反的事情：我想查詢所有可編輯菜單對象，其中不包含包含具有指定ID的頁面。迄今爲止，我還沒有找到解決方案。我還以爲上面的查詢的網頁部分的簡單顛倒就足夠導致：

// Only retrieve the required properties from Menu object 
ProjectionList menuViewProjections = Projections.ProjectionList() 
    .Add(Projections.Property("ID"), "ID") 
    .Add(Projections.Property("Name"), "Name") 
    .Add(Projections.Property("Description"), "Description"); 

var menus = session.CreateCriteria(typeof(Menu)) 
    // Only menu's that are editable 
    .Add(Restrictions.Eq("IsEditable", true)) 

    // Only project required properties 
    .SetProjection(menuViewProjections) 

    // Only retrieve menus that do NOT contain this referenced page 
    .CreateCriteria("Pages") 
    .Add(Restrictions.Not(Restrictions.Eq("ID", pageId))) 

    // Transform results into required view objects 
    .SetResultTransformer(Transformers.AliasToBean(typeof(MenuView))) 
    .List<MenuView>(); 

但是，這會導致下面的SQL：

SELECT this_.ID   as y0_, 
    this_.Name  as y1_, 
    this_.Description as y2_ 
FROM [Menu] this_ 
     inner join PagesInMenu pages3_ 
     on this_.ID = pages3_.MenuID 
     inner join [Page] page1_ 
     on pages3_.PageID = page1_.ID 
WHERE this_.IsEditable = 1 /* @p0 */ 
     and not (page1_.ID = 8 /* @p1 */) 

這仍然是返回菜單的結果做的項目包含一個id爲8的頁面。爲什麼邏輯的這種簡單逆轉在代碼方面並不那麼簡單？

[更新] 從Firo的建議，建議的查詢更改;

// Only retrieve menus that do NOT contain this referenced page 
.CreateCriteria("Pages") 
.Add(Subqueries.PropertyNotIn("Id", querymenuItemswithPage)) <--- query you have would be here 

現在生成下面的sql語句;

SELECT this_.ID   as y0_, 
     this_.Name  as y1_, 
     this_.Description as y2_ 
FROM [Menu] this_ 
     inner join PagesInMenu pages3_ 
     on this_.ID = pages3_.MenuID 
     inner join [Page] page1_ 
     on pages3_.PageID = page1_.ID 
WHERE this_.IsEditable = 1 /* @p0 */ 
     and page1_.ID not in (SELECT this_0_.ID as y0_ 
          FROM [Page] this_0_ 
          WHERE this_0_.ID = 1 /* @p1 */ 

）

起初似乎正是我想要的，但不幸的是（可能是由於我加入的理解差）仍然沒有回來完全是我想要的。給出下面的表

菜單

然後的PagesInMenu聯接表（具有WHERE子句WHERE PAGEID = 1）

我們可以看到ID爲1的頁面在菜單5和6中沒有被引用。我期待有問題的查詢僅返回單行，這將是編號，姓名，並用5號菜單的說明，因爲這是第1頁是不列入和是編輯

相反，只有菜單新的查詢返回;

我已經越過了被返回，但不應該成爲所有行。這裏發生了什麼 ！？

Answer 1

更新：

• 去除.CreateCriteria("Pages")

• 添加子查詢

  var querymenuItemswithPage = DetachedCriteria.For<Menu>() 
  .CreateCriteria("Pages") 
      .Add(Restrictions.Eq("ID", pageId)) 
  .SetProjection(Projections.Id()) 
  
  // Only retrieve the required properties from Menu object 
  ProjectionList menuViewProjections = Projections.ProjectionList() 
      .Add(Projections.Property("ID"), "ID") 
      .Add(Projections.Property("Name"), "Name") 
      .Add(Projections.Property("Description"), "Description"); 
  
  var menus = session.CreateCriteria(typeof(Menu)) 
      // Only menu's that are editable 
      .Add(Restrictions.Eq("IsEditable", true)) 
  
      // Only project required properties 
      .SetProjection(menuViewProjections) 
  
      // Only retrieve menus that do NOT contain this referenced page 
      .Add(Subqueries.PropertyNotIn("Id", querymenuItemswithPage)) 
  
      // Transform results into required view objects 
      .SetResultTransformer(Transformers.AliasToBean(typeof(MenuView))) 
      .List<MenuView>();