2016-07-28 134 views
0

我在我的網站上有視頻,我想展示他們使用Php和html5進行流媒體播放。使用PHP Html5流媒體視頻

我可以按照本教程 (http://codesamplez.com/programming/php-html5-video-streaming-tutorial)用php類創建流視頻。

<?php 
 
/** 
 
* Description of VideoStream 
 
* 
 
* @author Rana 
 
* @link http://codesamplez.com/programming/php-html5-video-streaming-tutorial 
 
*/ 
 
class VideoStream 
 
{ 
 
    private $path = ""; 
 
    private $stream = ""; 
 
    private $buffer = 102400; 
 
    private $start = -1; 
 
    private $end = -1; 
 
    private $size = 0; 
 
    
 
    function __construct($filePath) 
 
    { 
 
     $this->path = $filePath; 
 
    } 
 
     
 
    /** 
 
    * Open stream 
 
    */ 
 
    private function open() 
 
    { 
 
     if (!($this->stream = fopen($this->path, 'rb'))) { 
 
      die('Could not open stream for reading'); 
 
     } 
 
      
 
    } 
 
     
 
    /** 
 
    * Set proper header to serve the video content 
 
    */ 
 
    private function setHeader() 
 
    { 
 
     ob_get_clean(); 
 
     header("Content-Type: video/mp4"); 
 
     header("Cache-Control: max-age=2592000, public"); 
 
     header("Expires: ".gmdate('D, d M Y H:i:s', time()+2592000) . ' GMT'); 
 
     header("Last-Modified: ".gmdate('D, d M Y H:i:s', @filemtime($this->path)) . ' GMT'); 
 
     $this->start = 0; 
 
     $this->size = filesize($this->path); 
 
     $this->end = $this->size - 1; 
 
     header("Accept-Ranges: 0-".$this->end); 
 
      
 
     if (isset($_SERVER['HTTP_RANGE'])) { 
 
    
 
      $c_start = $this->start; 
 
      $c_end = $this->end; 
 
    
 
      list(, $range) = explode('=', $_SERVER['HTTP_RANGE'], 2); 
 
      if (strpos($range, ',') !== false) { 
 
       header('HTTP/1.1 416 Requested Range Not Satisfiable'); 
 
       header("Content-Range: bytes $this->start-$this->end/$this->size"); 
 
       exit; 
 
      } 
 
      if ($range == '-') { 
 
       $c_start = $this->size - substr($range, 1); 
 
      }else{ 
 
       $range = explode('-', $range); 
 
       $c_start = $range[0]; 
 
        
 
       $c_end = (isset($range[1]) && is_numeric($range[1])) ? $range[1] : $c_end; 
 
      } 
 
      $c_end = ($c_end > $this->end) ? $this->end : $c_end; 
 
      if ($c_start > $c_end || $c_start > $this->size - 1 || $c_end >= $this->size) { 
 
       header('HTTP/1.1 416 Requested Range Not Satisfiable'); 
 
       header("Content-Range: bytes $this->start-$this->end/$this->size"); 
 
       exit; 
 
      } 
 
      $this->start = $c_start; 
 
      $this->end = $c_end; 
 
      $length = $this->end - $this->start + 1; 
 
      fseek($this->stream, $this->start); 
 
      header('HTTP/1.1 206 Partial Content'); 
 
      header("Content-Length: ".$length); 
 
      header("Content-Range: bytes $this->start-$this->end/".$this->size); 
 
     } 
 
     else 
 
     { 
 
      header("Content-Length: ".$this->size); 
 
     } 
 
      
 
    } 
 
    
 
    /** 
 
    * close curretly opened stream 
 
    */ 
 
    private function end() 
 
    { 
 
     fclose($this->stream); 
 
     exit; 
 
    } 
 
     
 
    /** 
 
    * perform the streaming of calculated range 
 
    */ 
 
    private function stream() 
 
    { 
 
     $i = $this->start; 
 
     set_time_limit(0); 
 
     while(!feof($this->stream) && $i <= $this->end) { 
 
      $bytesToRead = $this->buffer; 
 
      if(($i+$bytesToRead) > $this->end) { 
 
       $bytesToRead = $this->end - $i + 1; 
 
      } 
 
      $data = fread($this->stream, $bytesToRead); 
 
      echo $data; 
 
      flush(); 
 
      $i += $bytesToRead; 
 
     } 
 
    } 
 
     
 
    /** 
 
    * Start streaming video content 
 
    */ 
 
    function start() 
 
    { 
 
     $this->open(); 
 
     $this->setHeader(); 
 
     $this->stream(); 
 
     $this->end(); 
 
    } 
 
}

所以,我有兩個問題:

1 - 我也想流的球員,但視頻是接管我的整個頁面,如何使視頻是隻是添加到我的html5播放器。

2 - 當我做一個URL HTTP視頻(http://video.newsmed.fr/pdv/0616.mp4)不起作用

感謝幫助我解決這個問題或建議我的其他解決方案的PHP。

回答

1
  1. 我也想流的球員,但視頻是接管我的整個>頁如何讓我的視頻是剛剛加入到我的HTML5播放器。

你剛纔複製HTML的例子,而不改變一個東西?看看HTML5的例子,你會看到theres width =「100%」,你可以改變你的值。

2 - 當我做,做一個url HTTP視頻(http://video.newsmed.fr/pdv/0616.mp4)>不行

的URL應該指向你的PHP代碼,而不是視頻文件的路徑。 例如:yourdomain.com/dir/your-php-file.php?video=0616.mp4

嘗試將您的php文件.php代碼,而不是您的問題videostream.php類。

-1

嘗試插入多達類之上

$stream = new VideoStream("file.mp4 or www//file.mp4"); 
$stream->start();exit;