所以目前我想弄清楚如何將下拉菜單添加到我在下面發佈的代碼中。我搜索了互聯網,但找不到一種適合我的方式,我對編碼很陌生,所以對其他人來說,這種方式很難實現。我將如何添加一個下拉菜單到我使用mysql的jquery表?
<table class="table table-bordered table-striped">
<thead> <!-- add class="thead-inverse" for a dark header -->
<tr>
<th>ID</th>
<th>USERNAME</th>
<th>Crime(s)</th>
<th>Active</th>
<th>EDIT</th>
</tr>
</thead>
<tfoot>
<tr>
</tr>
</div>
</th>
</tfoot>';
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td>'.$row["id"].'</td>
<td class="username" data-id1="'.$row["id"].'" contenteditable>'.$row["name"].'</td>
<td class="crime" data-id2="'.$row["id"].'" contenteditable>'.$row["crime"].'</td>
<td class="activated" data-id2="'.$row["id"].'" contenteditable>'.$row["activated"].'</td>
<td><button type="button" name="delete_btn" data-id3="'.$row["id"].'" class="btn btn-xs btn-danger btn_delete">DELETE</button></td>
</tr>
';
}
$output .= '
<tr>
<td></td>
<td id="name" contenteditable></td>
<td id="crime" contenteditable></td>
<td id="activated" contenteditable></td>
<td><button type="button" name="btn_add" id="btn_add" class="btn btn-xs btn-success">ADD ACCOUNT</button></td>
</tr>
';
}
else
{
$output .= '<tr>
<td colspan="4">Data not Found</td>
</tr>';
}
$output .= '</table>
</div>';
echo $output;
?>
爲了明確這一點,我想補充,當你在框中單擊正在積極將有幾個選項,一旦點擊下拉出現,您選擇,然後修改和更新的選項下拉。 –
http://prntscr.com/fqt7q2 –
你在哪裏試圖添加下拉菜單?它應該包含什麼值@ bluqe-bluqe – AceKYD