你可以做,通過使用命名本機查詢和結果集映射 ,這裏是一個完整的〔實施例
使命實體
package com.ntg.crm.internal.entites;
import java.math.BigInteger;
import java.util.List;
import javax.persistence.Entity;
import javax.persistence.EntityResult;
import javax.persistence.FetchType;
import javax.persistence.FieldResult;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.JoinTable;
import javax.persistence.ManyToMany;
import javax.persistence.NamedNativeQuery;
import javax.persistence.SqlResultSetMapping;
@SqlResultSetMapping(name = "Mission.findAllMissionsMapping", entities = @EntityResult(entityClass = Mission.class, fields = {
@FieldResult(name = "name", column = "mname"), @FieldResult(name = "id", column = "mid")
}))
@NamedNativeQuery(name = "Mission.findAllMissions", query = "select m.id as mid,m.name as mname , info.id uid ,info.name uname from Mission m join user_info_missions um on m.id "
+ "= um.missions_id join user_Info info on info.id = um.user_id where info.name =:userName", resultSetMapping = "Mission.findAllMissionsMapping")
@Entity
public class Mission {
public Mission() {
}
public Mission(BigInteger id, String name) {
super();
this.id = id;
this.name = name;
}
public Mission(BigInteger id, String name, List<User> users) {
super();
this.id = id;
this.name = name;
this.users = users;
}
@Id
BigInteger id;
String name;
@ManyToMany(fetch = FetchType.EAGER)
@JoinTable(name = "user_info_missions", joinColumns = @JoinColumn(name = "missions_id"), inverseJoinColumns = @JoinColumn(name = "user_id"))
List<User> users;
public BigInteger getId() {
return id;
}
public void setId(BigInteger id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public List<User> getUsers() {
return users;
}
public void setUsers(List<User> users) {
this.users = users;
}
}
用戶實體
package com.ntg.crm.internal.entites;
import java.util.List;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.JoinTable;
import javax.persistence.ManyToMany;
import javax.persistence.Table;
import com.fasterxml.jackson.annotation.JsonIgnore;
@Entity
@Table(name = "userInfo")
public class User {
@Id
long id;
String name;
@ManyToMany(targetEntity = Mission.class)
@JoinTable(name = "user_info_missions", joinColumns = @JoinColumn(name = "user_id"), inverseJoinColumns = @JoinColumn(name = "missions_id"))
@JsonIgnore
List<Mission> missions;
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public List<Mission> getMissions() {
return missions;
}
public void setMissions(List<Mission> missions) {
this.missions = missions;
}
}
存儲功能
public List<Mission> findAllMissions(@Param("userName") String userName);
控制器功能
@Autowired
TestRepository testRepo;
@RequestMapping(value = "", method = RequestMethod.GET, produces = "application/json", consumes = "application/json")
@ResponseBody
List<Mission> getall() {
List<Mission> missions = testRepo.findAllMissions("Test");
return missions;
}
,這是結果
[
{
"id": 1,
"name": "Mission 1",
"users": [
{
"id": 1,
"name": "Test"
}
]
},
{
"id": 2,
"name": "Mission 2",
"users": [
{
"id": 1,
"name": "Test"
}
]
}
]
感謝您的回答,但我想知道,如果查詢結果正確地映射到entitie使命。換句話說,我可以在請求後獲得用戶列表。 – midy62
是的,你可以得到一個用戶列表看到答案更新 –