根據值對列重新排序

Question

有什麼方法可以根據值對錶（或查詢）中的列重新排序。

例如，在每一行上，FacName應該是第一個，NPI - 第2個，TIN - 第3個和地址 - 第4個。

謝謝！

Answer 1

要移動列之間的數據的事實強烈地暗示出底層的數據模型被打破，需要進行標準化。修復數據模型比爲系統增加另一層複雜性要合適得多。

話雖這麼說，你應該能夠做到像

SELECT (CASE WHEN column1 LIKE 'FacilityName%' THEN column1 
      WHEN column2 LIKE 'FacilityName%' THEN column2 
      WHEN column3 LIKE 'FacilityName%' THEN column3 
      WHEN column4 LIKE 'FacilityName%' THEN column4 
      ELSE null 
     END) column1, 
     (CASE WHEN column1 LIKE 'NPI%' THEN column1 
      WHEN column2 LIKE 'NPI%' THEN column2 
      WHEN column3 LIKE 'NPI%' THEN column3 
      WHEN column4 LIKE 'NPI%' THEN column4 
      ELSE null 
     END) column2, 
     (CASE WHEN column1 LIKE 'TIN%' THEN column1 
      WHEN column2 LIKE 'TIN%' THEN column2 
      WHEN column3 LIKE 'TIN%' THEN column3 
      WHEN column4 LIKE 'TIN%' THEN column4 
      ELSE null 
     END) column3, 
     (CASE WHEN column1 LIKE 'Address%' THEN column1 
      WHEN column2 LIKE 'Address%' THEN column2 
      WHEN column3 LIKE 'Address%' THEN column3 
      WHEN column4 LIKE 'Address%' THEN column4 
      ELSE null 
     END) column4 
    FROM(<<your query>>) 

Answer 2

select col1, col2, col3, col4 from (
    select * from (
    select 
     n, str, row_number() over (partition by n order by 
     decode(substr(str,1,3),'Fac',1,'NPI',2,'TIN',3,'Add',4)) cn 
    from (
     select * from (select t.*, rownum n from t) 
     unpivot (str for cn in (col1 as 0, col2 as 0, col3 as 0, col4 as 0)) 
    ) 
) 
    pivot (min(str) for cn in (1 as col1, 2 as col2, 3 as col3, 4 as col4)) 
) 
order by n 

fiddle