Zend的像或條件

Question

我買了WHERE條件的SQL問題：

$select->where('(users.user_fname LIKE (?))','%'.$first.'%'); 

如何把它OR條件，因此看起來像：

$select->where('(users.user_fname LIKE (?))','%'.$first.'%'); 
OR 
$select->where('(users.user_fname LIKE (?))','%'.$last.'%'); 

Answer 1

http://framework.zend.com/manual/1.12/en/zend.db.select.html

$select 
    ->where('(users.user_fname LIKE "%?%")', $first) 
    ->orWhere('(users.user_fname LIKE "%?%")', $last) 
;