1
下面給出的是我所選擇的座標位置如何將選定位置的座標轉換爲php中的long lat?
(31.41804293752012,73.0742385238409),(31.414820024420457,73.07904504239559),(31.419031763657962,73.08410905301571),(31.422877099540145,73.0788304656744)
我想這些座標經度轉換和latitude..kindly幫我這個
我已存儲的各X座標成獨立的數組紐約座標轉換成單獨的數組下面 是我的代碼,會灌輸一些感覺,我在做什麼畢竟... 我只是需要知道如何轉換這些座標lat和長,然後將這些緯度郎街道地址.....
function check($point,$x_cordinates,$y_cordinates,$lat,$lon)
{
$i=$j=$k=0;
for ($i = 0, $j = $point-1; $i < $point; $j = $i++)
{
if (($y_cordinates[$i] > $lat_y != ($y_cordinates[$j] > $lat_y)) && ($lon_x < ($x_cordinates[$j] - $x_cordinates[$i]) * ($lat_y - $y_cordinates[$i])/($y_cordinates[$j] - $y_cordinates[$i]) + $x_cordinates[$i]))
{
$k = !$k;
}
}
return $k;
}
$office_id=24;
$sql="select office_loc from office where office_id='$office_id'LIMIT 1";
$que=mysql_query($sql);
if($que)
{
$row=mysql_fetch_array($que);
$loc=$row['office_loc'];
$loc_wdot_rbrac=explode('(',$loc);
$loc_wdot_lbrac=str_replace(')', '', $loc_wdot_rbrac);
$x_cordinates=array();
$y_cordinates=array();
foreach ($loc_wdot_lbrac as $value)
{
# code...
if (empty($value))
{
# code...
contine;
}
$loc_wdot_comma=explode(',',$value);
$x_cordinates[]=$loc_wdot_comma[0];
$y_cordinates[]=$loc_wdot_comma[1];
}
echo '---- Result x ---- <br /><pre>';
print_r($x_cordinates);
echo '</pre>';
echo '---- Result y ---- <br /><pre>';
print_r($y_cordinates);
echo '</pre>';
$lat=31.5546;
$lon=74.3572;
$point=count($x_cordinates);
if(check($point,$x_cordinates,$y_cordinates,$lat,$lon))
{
echo"inside";
}
else
{
echo"out";
}
}
else
{
echo mysql_error(db);
}
,這裏是輸出.....
---- Result x ----
Array
(
[0] =>
[1] => 31.41804293752012
[2] => 31.414820024420457
[3] => 31.419031763657962
[4] => 31.422877099540145
)
---- Result y ----
Array
(
[0] =>
[1] => 73.0742385238409
[2] => 73.07904504239559
[3] => 73.08410905301571
[4] => 73.0788304656744
)
out
什麼是預期的輸出? – Andreas
@Andreas我已經在代碼下面的問題中發佈了輸出......事情是我想要將這些座標轉換爲lon lat或如果可行然後直接地址 –
您可以嘗試使用Google APi的相同 – Apoorv