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我目前一直在嘗試在Tkinter中構建一個GUI應用程序,該應用程序從一個條目接收用戶輸入並從屬於一個下拉菜單。在萬阿英,蔣達清是,OptionMenu不斷拋出:python使用OptionMenu的TypeError Tkinter
Traceback (most recent call last):
File "C:/Python34/food2GUIree.py", line 70, in <module>
mealOneButton = Button(root, text = "query database", command = GetEntry(mealOneString))
File "C:/Python34/food2GUIree.py", line 68, in GetEntry
meal = OptionMenu(root, '', *getMeal).pack()
TypeError: __init__() missing 1 required positional argument: 'value'
當我更換getMeal在:
def GetEntry(x):
formatted = x.get().split()##gets the entry and forms a list
getMeal = CsvLoadSearch(u, formatted)
meal = OptionMenu(root, '', *getMeal).pack()
與列表= [1,2,3,4]或任何其他列表,它工作正常。爲什麼是這樣?
波紋管是完整的程序:
from tkinter import *
from tkinter import ttk
import csv
import os
u = "C:\\Users\\luke daniels\\Documents\\fooddata.csv"
"""
Loads csv and compares elements from foodList with current row.
returns a list of rows that match elements in foodList.
"""
def CsvLoadSearch(u, foodList):
results = []
inputfile = open(u)
for row in csv.reader(inputfile):
for food in foodList:
if food in row[0]:
results.append(row[0])
##print(row)
return results
root = Tk()
root.title("MacroCalc")
caloriesAim = StringVar()
protien = StringVar()
fat = StringVar()
carbs = StringVar()
mealOneString = StringVar()
mealTwoString = StringVar()
mealThreeString = StringVar()
mealFourString = StringVar()
mealFiveString = StringVar()
mealSixString = StringVar()
mealOneKeyword = Entry(root, textvariable = mealOneString)
mealTwoKeyword = Entry(root, textvariable = mealTwoString)
mealThreeKeyword = Entry(root, textvariable = mealThreeString)
mealFourKeyword = Entry(root, textvariable = mealFourString)
mealFiveKeyword = Entry(root, textvariable = mealFiveString)
mealSixKeyword = Entry(root, textvariable = mealSixString)
mealLabel = Label(root,text = "meals")
mealLabel.config(font=("Courier", 30))
mealLabel.pack()
mealLone = Label(root,text = "meal one")
mealLtwo = Label(root,text = "meal two")
mealLthree = Label(root,text = "meal three")
mealLfour = Label(root,text = "meal four")
mealLfive = Label(root,text = "meal five")
mealLsix = Label(root,text = "meal six")
caloriesLabel = Label(root,text = "calories needed").pack()
calories = Text(root, height = 1, width = 10).pack()
protienLabel= Label(root,text = "protien ratio").pack()
protien = Text(root, height = 1, width = 4).pack()
carbsLabel = Label(root,text = "carbohydrate ratio").pack()
carbs = Text(root, height = 1, width = 4).pack()
fatsLabel = Label(root,text = "fats ratio").pack()
fats = Text(root, height = 1, width = 4).pack()
displayText = Text(root).pack(side = RIGHT)
def GetEntry(x):
formatted = x.get().split()##gets the entry and forms a list
getMeal = CsvLoadSearch(u, formatted)
meal = OptionMenu(root, '', *getMeal).pack()
mealOneButton = Button(root, text = "query database", command = GetEntry(mealOneString))
mealTwoButton = Button(root, text = "query database", command = GetEntry(mealTwoString))
mealThreeButton = Button(root, text = "query database", command = GetEntry(mealThreeString))
mealFourButton = Button(root, text = "query database", command = GetEntry(mealFourString))
mealFiveButton = Button(root, text = "query database", command = GetEntry(mealFiveString))
mealSixButton = Button(root, text = "query database", command = GetEntry(mealSixString))
mealButtons = [mealOneButton, mealTwoButton, mealThreeButton, mealFourButton, mealFiveButton, mealSixButton]
mealKeywords = [mealOneKeyword, mealTwoKeyword, mealThreeKeyword, mealFourKeyword, mealFiveKeyword, mealSixKeyword]
mealLabels = [mealLone, mealLtwo, mealLthree, mealLfour, mealLfive, mealLsix]
##meals = [mealOne, mealTwo, mealThree, mealFour, mealFive, mealSix]
##packs the drop downs and respective lables
i = 0
while i < len(mealLabels):
mealLabels[i].pack()
mealKeywords[i].pack()
mealButtons[i].pack()
##meal.pack()
i = i + 1
root.mainloop()
是否已確認'getMeal'包含你假定它包含的內容的按鈕時,命令後需要lambda函數?錯誤意味着它是空的。 –
打印'getMeal',你得到那個錯誤,因爲它是空的。 –
請考慮減少示例的大小。如果問題出在一個'OptionMenu'上,你可能會刪除所有其他的小部件和'StringVar's,並且你可以硬編碼你傳給'OptionMenu'的參數。 –