我有一個while循環打印多個複選框..我將它們改爲checkbox而不是單選按鈕..現在我想要做的就是將所有這些複選框的名稱傳遞給我的投票.php文件。如果我在我的循環中給我的複選框輸入一個簡單的名字,然後將它傳遞給我的vote.php,它處理我所有的POST數據,它只會繼續我最後的選擇。我想要我所有的選擇。我清理了我的代碼給你們一點點。試圖讓多個單選按鈕通過表單
告訴我在哪裏,我錯了here..here正在打印按鈕我最初的代碼..
while($row_nominee=mysql_fetch_array($result_nominee)){
$id = $row_nominee[0];
//print "$level";
$prefix = $row_nominee[1];
$fname = $row_nominee[2];
$lname = $row_nominee[3];
$suffix = $row_nominee[4];
$city = $row_nominee[5];
$state = $row_nominee[6];
$zip = $row_nominee[7];
$bio = $row_nominee[8];
$level = $row_nominee[10];
$name = $prefix . " " . $fname . " " . $lname;
$address = $city . " " . $state . " " . $zip;
//print "$voted";
print "<tr>";
print "<td width=\"4\" valign=\"top\"><input type=\"checkbox\" name=\"candidateOne\" id=\"candidate\" value=$id></td>";
print "<td valign=\"top\"><FONT face=Tahoma,Arial,Helv size=-1><b>Name:</b> <font color=\"#ff0000\">$name</font><br><b>Hometown:</b> $address<br><b>Bio:<br /></b> $bio</font></td>";
print "</tr>";
}
?>
//now here is my vote.php file which handles the checkboxes.
//get the contents from the vote ballot Form
$voter_id = safeEscapeString(qsrequest(voter));
$candidate_id = safeEscapeString(qsrequest(candidateOne));
//print "$voter_id and $candidate_id";
include '../../sql/usagym_connection.php';
if(qsrequest(correct))
{
$voter_id1= safeEscapeString(qsrequest(voter1));
$candidate_id1= safeEscapeString(qsrequest(candidate1));
$votes1= safeEscapeString(qsrequest(votes1));
$votes1 += 1;
$sql_voter = "update stateChair_voters set voted='Y' where (usagnum='$voter_id1')";
//print "$sql_voter<br>";
$result_voter = mysql_query($sql_voter, $link) or die("Invalid query2");
$update_candidate = "update stateChair_nominees set votes=$votes1 where (id=$candidate_id1)";
//print "$update_candidate<br>";
$result_update = mysql_query($update_candidate, $link) or die("Invalid query3");
//print "Total votes is $votes1.";
header("Location: vote_thanks.html");
exit;
}
else
{
//connect the database
$sql_candidate = "select id, prefix, fname, lname, suffix, city, state, zip, bio, votes from stateChair_nominees where id=$candidate_id";
$result_candidate = mysql_query($sql_candidate, $link) or die("Invalid query1". mysql_error());
while($row_candidate=mysql_fetch_array($result_candidate)){
$id = $row_candidate[0];
$prefix = $row_candidate[1];
$fname = $row_candidate[2];
$lname = $row_candidate[3];
$suffix = $row_candidate[4];
$city = $row_candidate[5];
$state = $row_candidate[6];
$zip = $row_candidate[7];
$bio = $row_candidate[8];
$votes = $row_candidate[9];
$name = $prefix . " " . $fname . " " . $lname;
$address = $city . " " . $state . " " . $zip;
}
?>
我真正想要做的就是多人提交表決而不只是一個人。思考?多謝你們!
這是我爲我的複選框代碼..
print "<td width=\"4\" valign=\"top\"><input type=\"checkbox\" name=\"candidateOne\" id=\"candidate\" value=$id></td>";
現在,這裏是處理這些checkboxes..I沒有寫這個代碼,我有調試它的代碼,所以任何幫助讚賞。
$candidate_id = safeEscapeString(qsrequest(candidateOne));
此代碼現在處理一個字符串,而不是一個變量。有什麼過程中有一個變量代表在另一個文件上的多個複選框,而在這裏錄製它們?
這個問題有點令人困惑,因爲你顯示了你所有的服務器端代碼,沒有關於單選按鈕。如果您嘗試從表單輸入中收集多個人,請使用複選框而不是單選按鈕。 – kinakuta
你可以整理你的源代碼,所以它更容易閱讀,請。 –
對不起,我把它清理了一下。 – wowzuzz