顯然我們應該在這裏使用Enumerable#sort_by
。
a = [
{
"id"=>1,
"popularity"=>7.77030797174916,
"title"=>"Another film",
},
{
"id"=>2,
"popularity"=>2.7703074916,
"title"=>"A film",
},
{
"id"=>3,
"popularity"=>9.77030797174916,
"title"=>"A third film",
}
]
a.sort_by{|h| h["popularity"]}
# => [{"id"=>2, "popularity"=>2.7703074916, "title"=>"A film"},
# {"id"=>1, "popularity"=>7.77030797174916, "title"=>"Another film"},
# {"id"=>3, "popularity"=>9.77030797174916, "title"=>"A third film"}]
或者我還可以使用Enumerable#sort
:
a = [
{
"id"=>1,
"popularity"=>7.77030797174916,
"title"=>"Another film",
},
{
"id"=>2,
"popularity"=>2.7703074916,
"title"=>"A film",
},
{
"id"=>3,
"popularity"=>9.77030797174916,
"title"=>"A third film",
}
]
a.sort{|h1,h2| h1["popularity"] <=> h2["popularity"]}
# => [{"id"=>2, "popularity"=>2.7703074916, "title"=>"A film"},
# {"id"=>1, "popularity"=>7.77030797174916, "title"=>"Another film"},
# {"id"=>3, "popularity"=>9.77030797174916, "title"=>"A third film"}]
BENCHMARK
require 'benchmark'
a = [
{
"id"=>1,
"popularity"=>7.77030797174916,
"title"=>"Another film",
},
{
"id"=>2,
"popularity"=>2.7703074916,
"title"=>"A film",
},
{
"id"=>3,
"popularity"=>9.77030797174916,
"title"=>"A third film",
}
]
Benchmark.bm(100) do |b|
b.report("Sort") { a.sort{|h1,h2| h1["popularity"] <=> h2["popularity"]} }
b.report("Sort by") { a.sort_by{|h| h["popularity"]} }
end
user system total real
Sort 0.000000 0.000000 0.000000 ( 0.000041)
Sort by 0.000000 0.000000 0.000000 ( 0.000019)
使用'sort_by',然後寫一個翻出普及塊 –