PHP的麻煩獲取內容+ API

Question

我想創建一個Adfly shortener網站，供我的同事使用PHP使用。我認爲這會很簡單，但我有一些麻煩得到這個工作

$longURL = $_GET['longurl']; 

$shortURL = shortAdfly($longURL); 

// Print the result 
print_r($shortURL); 

// Adf.ly shortener 
function shortAdfly($ToConvert) { 
    urlencode($ToConvert); 
    $apiUrl = 'http://api.adf.ly/api.php?' . http_build_query([ 
    'key' => 'My API Key', 
    'uid' => 'My User ID', 
    'advert_type' => 'int', 
    'domain' => 'adf.ly', 
    'url' => $ToConvert ]); 
    $short_url = file_get_contents($apiUrl); 
    return $short_url; 
} 

Answer 1

手動構建URL查詢字符串就像手工編碼JSON;你不應該這樣做。使用提供

$apiUrl = 'http://api.adf.ly/api.php?' . http_build_query([ 
    'key'   => 'your-api-key', 
    'uid'   => 1234567, 
    'advert_type' => 'int', 
    'domain'  => 'adf.ly', 
    'url'   => $ToConvert 
]); 
return file_get_contents($apiUrl);