XML - DTD，兩個元素相同的屬性

Question

爲什麼下面的代碼不正確？ XMLSPY發現錯誤的元素員工

<!ELEMENT personnel (contractor*,employee*,partner*)+ > 
<!ELEMENT contractor (info)> 
<!ELEMENT employee(info)> 
<!ATTLIST info lname CDATA #REQUIRED fname CDATA #REQUIRED hiredate CDATA #REQUIRED firedate CDATA #REQUIRED> 

Answer 1

你需要employee後的空間。

info元素也未定義。

如果你正在嘗試做的就是在contractor和employee屬性，那麼這個做的：

<!ELEMENT personnel (contractor*, employee*, partner*)+ > 
<!ELEMENT contractor EMPTY> 
<!ELEMENT employee EMPTY> 
<!ATTLIST contractor lname CDATA #REQUIRED fname CDATA #REQUIRED hiredate CDATA #REQUIRED firedate CDATA #REQUIRED> 
<!ATTLIST employee lname CDATA #REQUIRED fname CDATA #REQUIRED hiredate CDATA #REQUIRED firedate CDATA #REQUIRED> 

這是有效的每DTD以上：

<personnel> 
    <employee lname="Foo" fname="Bar" firedate="1" hiredate="2"/> 
    <contractor lname="Foo" fname="Bar" firedate="1" hiredate="2"/> 
</personnel> 

或者你可以共享這樣的屬性聲明：

<!ENTITY % shared "lname CDATA #REQUIRED fname CDATA #REQUIRED hiredate CDATA #REQUIRED firedate CDATA #REQUIRED"> 
<!ELEMENT personnel (contractor*, employee*, partner*)+ > 
<!ELEMENT contractor EMPTY> 
<!ELEMENT employee EMPTY> 
<!ATTLIST contractor %shared;> 
<!ATTLIST employee %shared;> 

This w ay如果您需要更改屬性列表，它將同時更改爲contractor和employee。