Android上的EditText上的電子郵件地址驗證

Question

如何在中執行Email Validationandroid？我已經通過谷歌& SO，但我沒有找到一個簡單的方法來驗證它。

Answer 1

要執行電子郵件驗證我們有很多方法，但簡單的&最簡單的方法是兩種方法。

1-使用EditText(....).addTextChangedListener其一直在EditText box即EMAIL_ID上的每個輸入觸發是無效或有效使用if-else條件

/** 
* Email Validation ex:- tech@end.com 
*/ 


final EditText emailValidate = (EditText)findViewById(R.id.textMessage); 

final TextView textView = (TextView)findViewById(R.id.text); 

String email = emailValidate.getText().toString().trim(); 

String emailPattern = "[a-zA-Z0-9._-]+@[a-z]+\\.+[a-z]+"; 

emailValidate .addTextChangedListener(new TextWatcher() { 
    public void afterTextChanged(Editable s) { 

    if (email.matches(emailPattern) && s.length() > 0) 
     { 
      Toast.makeText(getApplicationContext(),"valid email address",Toast.LENGTH_SHORT).show(); 
      // or 
      textView.setText("valid email"); 
     } 
     else 
     { 
      Toast.makeText(getApplicationContext(),"Invalid email address",Toast.LENGTH_SHORT).show(); 
      //or 
      textView.setText("invalid email"); 
     } 
    } 
    public void beforeTextChanged(CharSequence s, int start, int count, int after) { 
    // other stuffs 
    } 
    public void onTextChanged(CharSequence s, int start, int before, int count) { 
    // other stuffs 
    } 
}); 

2-簡單的方法。使用getText（）獲取EditText框字符串，並與爲電子郵件提供的模式進行比較。如果模式不匹配或macthes，onClick按鈕烤麪包消息。它不會觸發EditText框中每個字符的輸入。簡單的例子如下所示。

final EditText emailValidate = (EditText)findViewById(R.id.textMessage); 

final TextView textView = (TextView)findViewById(R.id.text); 

String email = emailValidate.getText().toString().trim(); 

String emailPattern = "[a-zA-Z0-9._-]+@[a-z]+\\.+[a-z]+"; 

// onClick of button perform this simplest code. 
if (email.matches(emailPattern)) 
{ 
Toast.makeText(getApplicationContext(),"valid email address",Toast.LENGTH_SHORT).show(); 
} 
else 
{ 
Toast.makeText(getApplicationContext(),"Invalid email address", Toast.LENGTH_SHORT).show(); 
} 

Answer 2

使用此方法驗證您的電子郵件格式。將電子郵件作爲字符串傳遞，如果格式正確則返回true，否則返回false。

/** 
* validate your email address format. Ex-akhi@mani.com 
*/ 
public boolean emailValidator(String email) 
{ 
    Pattern pattern; 
    Matcher matcher; 
    final String EMAIL_PATTERN = "^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$"; 
    pattern = Pattern.compile(EMAIL_PATTERN); 
    matcher = pattern.matcher(email); 
    return matcher.matches(); 
} 

Answer 3

試試這個：

if (!emailRegistration.matches("[a-zA-Z0-9._-]+@[a-z]+.[a-z]+")) { 
    editTextEmail.setError("Invalid Email Address"); 
} 

Answer 4

試試這個

public static final Pattern EMAIL_ADDRESS_PATTERN = Pattern.compile(

       "[a-zA-Z0-9\\+\\.\\_\\%\\-\\+]{1,256}" + 
       "\\@" + 
       "[a-zA-Z0-9][a-zA-Z0-9\\-]{0,64}" + 
       "(" + 
       "\\." + 
       "[a-zA-Z0-9][a-zA-Z0-9\\-]{0,25}" + 
       ")+" 
     ); 

和TNE編輯文本

final String emailText = email.getText().toString(); 
EMAIL_ADDRESS_PATTERN.matcher(emailText).matches() 

Answer 5

public static boolean isEmailValid(String email) { 
    boolean isValid = false; 

    String expression = "^[\\w\\.-]+@([\\w\\-]+\\.)+[A-Z]{2,4}$"; 
    CharSequence inputStr = email; 

    Pattern pattern = Pattern.compile(expression, Pattern.CASE_INSENSITIVE); 
    Matcher matcher = pattern.matcher(inputStr); 
    if (matcher.matches()) { 
     isValid = true; 
    } 
    return isValid; 
} 

Answer 6

這是一個示例我thod我創建驗證電子郵件地址，如果傳遞的字符串參數是一個有效的電子郵件地址，它返回true，否則返回false。

private boolean validateEmailAddress(String emailAddress){ 
    String expression="^[\\w\\-]([\\.\\w])+[\\w]+@([\\w\\-]+\\.)+[A-Z]{2,4}$"; 
     CharSequence inputStr = emailAddress; 
     Pattern pattern = Pattern.compile(expression,Pattern.CASE_INSENSITIVE); 
     Matcher matcher = pattern.matcher(inputStr); 
     return matcher.matches(); 
} 

Answer 7

這太容易了：

添加此方法電子郵件地址到檢查是否有效或不：

private boolean isValidEmaillId(String email){ 

    return Pattern.compile("^(([\\w-]+\\.)+[\\w-]+|([a-zA-Z]{1}|[\\w-]{2,}))@" 
       + "((([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?" 
       + "[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\." 
       + "([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?" 
       + "[0-9]{1,2}|25[0-5]|2[0-4][0-9])){1}|" 
       + "([a-zA-Z]+[\\w-]+\\.)+[a-zA-Z]{2,4})$").matcher(email).matches(); 
    } 

現在用字符串檢查EditText上 的：

if(isValidEmaillId(edtEmailId.getText().toString().trim())){ 
    Toast.makeText(getApplicationContext(), "Valid Email Address.", Toast.LENGTH_SHORT).show(); 
}else{  
    Toast.makeText(getApplicationContext(), "InValid Email Address.", Toast.LENGTH_SHORT).show(); 
} 

完成

Answer 8

public final static boolean isValidEmail(CharSequence target) { 
    return (!TextUtils.isEmpty(target) && Patterns.EMAIL_ADDRESS.matcher(target).matches()); 
} 

編輯::它將工作在Android 2.2+起！ 編輯：添加缺少;

Answer 9

使用此方法來驗證EMAIL： -

public static boolean isEditTextContainEmail(EditText argEditText) { 

      try { 
       Pattern pattern = Pattern.compile("^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$"); 
       Matcher matcher = pattern.matcher(argEditText.getText()); 
       return matcher.matches(); 
      } catch (Exception e) { 
       e.printStackTrace(); 
       return false; 
      } 
     } 

讓我知道如果您有任何疑問？