如何驗證數組列表的字符串值的升序？

Question

我正在使用Selenium Webdriver和Java綁定，並且正在測試排序功能，因此您將值排列在arraylist = {"4"","4.5"","5.5""}中。所以基本上該字符串包含小數點以及雙引號。我有下面的代碼。問題在於，由於事實上，當它比較當前和以前的事實時，我得到錯誤。感謝您的幫助

public Boolean checkAscendingOrderScreensize(List<String> list){ 
    if(list == null || list.isEmpty()) 
     return false; 
    if(list.size() == 1) 
     return true; 
    for(int i=1; i<list.size();i++) 
    { 
     String current = list.get(i).toString(); 
     String previous = list.get(i-1).toString(); 
     current = current.replace(",","."); 
     current = current.replace("\"", ""); 
     previous = previous.replace(",","."); 
     previous = previous.replace("\"", ""); 

     if(current.compareTo(previous)>0) 
       return false; 
    } 
    return true; 
} 

Answer 1

您需要在轉換之前將字符串轉換爲double。因此，解決辦法將是

public class Main { 

    public static void main(String bicycle[]) { 
     List<String> texts = new ArrayList<String>(); 
     texts.add("4\""); 
     texts.add("4.5\""); 
     texts.add("5.5\""); 
     System.out.println(checkAscendingOrderScreensize(texts)); 
      // prints true 

    } 

    public static boolean checkAscendingOrderScreensize(List<String> list) { 

     if (list == null || list.isEmpty()) 
      return false; 

     if (list.size() == 1) 
      return true; 

     for (int i = 1; i < list.size(); i++) { 
      String current = list.get(i).toString(); 
      String previous = list.get(i - 1).toString(); 
      current = current.replace(",", "."); 
      current = current.replace("\"", ""); 
      previous = previous.replace(",", "."); 
      previous = previous.replace("\"", ""); 

      if(Double.valueOf(current)<Double.valueOf(previous)) 


       return false; 
     } 

     return true; 
    } 

}