Python的子進程：如何隱藏終端窗口並仍然捕獲輸出？

Question

此代碼的工作，但終端窗口彈出（簡述）：

print 'Trying wireless' 
while True: 
    wlan = subprocess.Popen("netsh wlan connect name='BSD'", stdout = subprocess.PIPE, stderr = subprocess.PIPE) 
    out, error = wlan.communicate() 
    if out.find('success') >=0: break 
    print "Still trying wireless..." 
    time.sleep(0.5) 
print "Connected!" 

這是Python 2.7版在Windows 7

任何辦法阻止彈出窗口，並保持抓住輸出？

謝謝， 尼克。

Answer 1

我沒有爲此設置，但由於沒有答案，我發現一些模糊的承諾in the docs。你可以試試這個：

si = subprocess.STARTUPINFO() 
si.dwFlags = subprocess.STARTF_USESHOWWINDOW # tell windows to use wShowWindow options 
si.wShowWindow = subprocess.SW_HIDE # ShowWindow option - only one that sounded useful 
wlan = subprocess.Popen(...., startupinfo=si) # as before but add the startupinfo argument