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試圖從PHP引入數據。我正在使用網址來顯示圖片,然後我正在使用這些標籤重新排列我嘗試創建的數據。我不確定我是否正確解析。如何JSON解析多元素數組?
var data = [];
function importJson(str) {
if (str == "") {
document.getElementById("content").innerHTML = "";
return;
}
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else { // code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
data = JSON.parse(xmlhttp.response);
alert(xmlhttp.response);
alert(data);
for (var sport_index = 0; sport_index < data.sport.length; sport_index++) {
var url1 = data.sport[sport_index][1];
alert(data.sport);
}
alert(url1);
}
}
xmlhttp.open("GET", "http://server/~name/folder/many.php");
xmlhttp.responseType = "json";
xmlhttp.send();
function buildImage(imagesrc) {
var img = document.createElement('img');
img.src = imagesrc;
document.getElementById('content').appendChild(img);
}
}
xmlhttp.response看起來像這樣
{"sport":[{"ImagesId":"34","ImagesPath":"http:\/\/server\/~name\/folder\/images\/24-08-2014-1408868419.png","Tag":"sport"},{"ImagesId":"30","ImagesPath":"http:\/\/server\/~name\/folder\/images\/23-08-2014-1408824125.png","Tag":"sport"}],"clothes":[{"ImagesId":"33","ImagesPath":"http:\/\/server\/~name\/folder\/images\/23-08-2014-1408824179.png","Tag":"clothes"},{"ImagesId":"32","ImagesPath":"http:\/\/server\/~name\/folder\/images\/23-08-2014-1408824166.png","Tag":"clothes"}],"food":[{"ImagesId":"31","ImagesPath":"http:\/\/server\/~name\/folder\/images\/23-08-2014-1408824158.png","Tag":"food"}]}
但數據貌似[object Object]
,當我嘗試使用URL來創建圖像的元素是不確定的。
所有是正確的,只是你必須通過名稱,而不是索引來訪問對象的屬性。 'var url1 = data.sport [sport_index] [1]'應該是'var url1 = data.sport [sport_index] .ImagesPath' – 2014-08-28 23:18:37
'JSON.parse()'應該沒問題。如果你不確定輸出對象,你可以嘗試用'JSON.stringify()'來顯示它。 – 2014-08-28 23:18:42
@cookiemonster你是對的。 – James121 2014-08-28 23:21:39