我有我的MainAcitivity
內部下面的代碼使用方法jsnrqstr.sendRequest(username, password, URL);
如何使用HTTPPost沒有新的可運行線程
loginButton.setOnClickListener(
new View.OnClickListener()
{
public void onClick(View view)
{
username = userNameBox.getText().toString();
password = passwordBox.getText().toString();
login_state = jsnrqstr.sendRequest(username, password, URL);
if(login_state.equals("ok")){
details.setUserName(username);
details.setPassword(password);
Toast.makeText(MainActivity.this, "User Verified", Toast.LENGTH_LONG).show();
passwordBox.setText("");
Intent myIntent = new Intent(MainActivity.this, DashBoardActivity.class);
MainActivity.this.startActivity(myIntent);
}else
Toast.makeText(MainActivity.this, "Login Unsuccessful", Toast.LENGTH_LONG).show();
passwordBox.setText("");
}
});
此方法使用下面的代碼,用於接收拍攝的用戶名和密碼登錄到應用程序從一個Erlang服務器響應該響應與JSON對象,我可以從它接收login_state。代碼jsnrqstr.sendRequest(username, password, URL);
public class JSONRequester {
String state;
public String sendRequest(final String userName, final String password, final String URL){
new Thread(new Runnable() {
public void run() {
HttpClient client = new DefaultHttpClient();
HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000); //Timeout Limit
HttpResponse response;
JSONObject json = new JSONObject();
try{
HttpPost post = new HttpPost(URL);
post.setHeader("Content-type", "application/json");
json.put("username", userName);
json.put("password", password);
StringEntity se = new StringEntity(json.toString());
se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
post.setEntity(se);
response = client.execute(post);
/*Checking response */
if(response!=null){
String temp = EntityUtils.toString(response.getEntity()); //Get the data in the entity
//Log.v("response", temp);
JsonObject o = new JsonParser().parse(temp).getAsJsonObject();
Log.v("response", o.get("state").toString());
state = o.get("state").toString();
}}
catch(Exception e){
e.printStackTrace();
//createDialog("Error", "Cannot Estabilish Connection");
}
}
}).start();
return state;
}
但我得到以下空指針異常 @
if(login_state.equals("ok")){
線,這意味着我沒有正確地返回從上述方法login_state
值。因爲我認爲這是因爲當時的新運行的線程返回值爲時已晚。我能做些什麼來解決這個問題?
謝謝。有效。 – ssrp