將二進制字符串轉換爲NSInteger

Question

任何人在Objective-C中都有一些代碼將二進制字符串轉換爲NSInteger？

例如：

111000 -> 56 

Answer 1

const char* utf8String = [binaryString UTF8String]; 
const char* endPtr = NULL; 
long int foo = strtol(utf8String, &endPtr, 2); 

if (endPtr != utf8String + strlen(utf8String)) 
{ 
    // string wasn't entirely a binary number 
} 
if (errno == ERANGE && (foo == LONG_MAX || foo == LONG_MIN)) 
{ 
    // number was too big or too small 
}