我知道如果將它作爲方法參數包含在內,Spring會將主體傳遞給控制器的方法。Spring Security - 實現UserDetailsService
我試圖通過實施UserDetailsService
擴展這個功能:
我創建了一個名爲CustomUserDetails
類,它擴展org.springframework.security.core.userdetails.User
我創建了一個名爲CustomUserDetailsService
服務實現UserDetailsService
異常
HTTP狀態500 - 請求處理失敗;嵌套的異常是 java.lang.ClassCastException: org.springframework.security.authentication.UsernamePasswordAuthenticationToken 不能轉換到com.demo.model.CustomUserDetails
在我的控制器方法下面的行拋出異常:
CustomUserDetails userDetails = (CustomUserDetails) principal;
Controller.java
@RequestMapping(value = "/dashboard", method = RequestMethod.GET)
public ModelAndView displayHomePage(ModelAndView modelAndView, Principal principal, HttpServletRequest request) {
// Throws exception here
CustomUserDetails userDetails = (CustomUserDetails) principal;
System.out.println(userDetails.getFirstName());
// Tried this and it also throws exception
// User cannot be cast to CustomUserDetails
//Authentication auth = SecurityContextHolder.getContext().getAuthentication();
//CustomUserDetails userDetails = (CustomUserDetails)auth.getPrincipal();
// Render template located at
// src/main/resources/templates/dashboard.html
modelAndView.setViewName("dashboard");
return modelAndView;
}
SecurityConfiguration.java
@Configuration
@EnableWebSecurity
public class SecurityConfiguration extends WebSecurityConfigurerAdapter {
@Autowired
private BCryptPasswordEncoder bCryptPasswordEncoder;
@Autowired
private DataSource dataSource;
@Value("${spring.queries.users-query}")
private String usersQuery;
@Value("${spring.queries.roles-query}")
private String rolesQuery;
@Autowired
SecurityHandler successHandler;
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.jdbcAuthentication().usersByUsernameQuery(usersQuery).authoritiesByUsernameQuery(rolesQuery)
.dataSource(dataSource).passwordEncoder(bCryptPasswordEncoder);
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests().antMatchers("/").permitAll().antMatchers("/register*").permitAll()
.antMatchers("/reset").permitAll().antMatchers("/forgot").permitAll().antMatchers("/grid").permitAll()
.antMatchers("/login").permitAll().antMatchers("/admin/**").hasAuthority("ADMIN").anyRequest()
.authenticated().and().formLogin().loginPage("/login").failureUrl("/login?error")
.defaultSuccessUrl("/dashboard").successHandler(successHandler).usernameParameter("email")
.passwordParameter("password").and().logout().logoutRequestMatcher(new AntPathRequestMatcher("/logout"))
.logoutSuccessUrl("/login?logout").and().exceptionHandling().accessDeniedPage("/access-denied");
}
@Override
public void configure(WebSecurity web) throws Exception {
web.ignoring().antMatchers("/error**", "/resources/**", "/static/**", "/css/**", "/js/**", "/img/**");
}
}
CustomUserDetails.java
public class CustomUserDetails extends org.springframework.security.core.userdetails.User {
public CustomUserDetails(String username, String password,
Collection<? extends GrantedAuthority> authorities) {
super(username, password, authorities);
}
private String firstName;
private String lastName;
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
}
CustomUserDetailsService.java
@Service
public class CustomUserDetailsService implements UserDetailsService{
@Override
public UserDetails loadUserByUsername(String userName) throws UsernameNotFoundException{
if(StringUtils.isEmpty(userName))
throw new UsernameNotFoundException("User name is empty");
//if you don't use authority based security, just add empty set
Set<GrantedAuthority> authorities = new HashSet<>();
CustomUserDetails userDetails = new CustomUserDetails(userName, "", authorities);
userDetails.setFirstName("Testing: " + new Date());
return userDetails;
}
}
的'Principal'你得到的是'Authentication'對象,而不是你的用戶。在那你可以調用'getPrincipal'來獲得實際的用戶。 (這也是類拋出異常告訴你的)。 –
你可以發佈實際拋出異常的代碼嗎? – rptmat57
@ rptmat57當然我添加了控制器方法代碼 –