在數組中使用split（）單獨的字符串和Ints

Question

我正在嘗試使用split()方法將字符串和整數與數組分開，但無法使其工作。

我在第7行得到Index Of Bound異常，它說的surname = list[1];，不知道爲什麼？

我試圖最終做的是拆分每個元素並獲得整數的平均值，以便文件中的第一行文本將讀取Mildred Bush 45 65 45 67 65和我寫入的新文本行一個新的文件會讀取布什，Mildred：最終得分是x.xx.

我已經嘗試了很長一段時間，現在可以只是根本不讓它工作。

我的代碼：

public static void splitTest() 
{ 
String forename, surname, tempStr, InputFileName, OutputFileName, nextLine; 
    int sum = 0; 
    float average; 
    //forename = "Mildred"; 
    //surname = "Bush"; 
    nextLine = ""; 
    tempStr = ""; 

    String[] list = tempStr.split(" "); 
    String[] list = new String[12]; 
    forename = list[0]; 
    surname = list[1]; 
    int[] scores = new int[5]; 
    scores[0] = Integer.parseInt(list[2]); 
    scores[1] = Integer.parseInt(list[3]); 
    scores[2] = Integer.parseInt(list[4]); 
    scores[3] = Integer.parseInt(list[5]); 
    scores[4] = Integer.parseInt(list[6]); 

    FileReader fileReader = null; 
    BufferedReader bufferedReader = null; 
    FileOutputStream outputStream = null; 
    PrintWriter printWriter = null; 
    clrscr(); 

    // Prompt user for input filename 
    System.out.println("Please enter the name of the file that is to be READ (e.g. details.txt) : "); 
    InputFileName = Genio.getString(); 

    // Prompt user for output filename 
    System.out.println("Please enter the name of the file that is to be WRITTEN TO (e.g. newDetails.txt) : "); 
    OutputFileName = Genio.getString(); 
    try { 
     // Open input file 
     fileReader = new FileReader(InputFileName); 
     bufferedReader = new BufferedReader(fileReader); 

     // Open output file 
     outputStream = new FileOutputStream(OutputFileName); 
     printWriter = new PrintWriter(outputStream); 

     // Read a line 
     tempStr = bufferedReader.readLine(); 

     // While there are lines in the input file 
     while (tempStr != null) { 
      String[] list; 
      list = tempStr.split(" "); 
      surname = list[0]; 
      forename = list[1]; 
      int[] scores = new int[5]; 
      scores[0] = Integer.parseInt(list[2]); 
      scores[1] = Integer.parseInt(list[3]); 
      scores[2] = Integer.parseInt(list[4]); 
      scores[3] = Integer.parseInt(list[5]); 
      scores[4] = Integer.parseInt(list[6]); 

      for(int i=0; i < scores.length; i++){ 
       sum = sum + scores[i]; 

       average = (float)sum/scores.length; 
       // Print it to screen 
       System.out.println(tempStr); 

       // Write it to the output file + a new-line 
       printWriter.write(tempStr +"\n"); 

       // Read a line 
       tempStr = bufferedReader.readLine(); 

       System.out.println("\n\nYOUR NEW FILE DATA IS DISPLAYED ABOVE!\n\n"); 
       pressKey(); 

       // Close the input file 
       bufferedReader.close(); 

       // Close the output file 
       printWriter.close(); 
      } 
     } 

凡說Genio，這與用戶輸入涉及一類。謝謝！

Answer 1

你的問題是

String[] list = tempStr.split(" "); 
String[] list = new String[12]; 

將其更改爲

String[] list = tempStr.split(" "); 

刪除String[] list = new String[12];

在這裏，你是分裂的刺痛，然後當你做String[] list = new String[12];你覆蓋的價值陣列！

另外

while (tempStr != null) { 

是一個無限循環。您將需要修復的..

，張貼在評論tempStr = "";當你選擇把它分解這會給你帶長度爲1的字符串，你應該將其更改爲tempStr = "Mildred Bush 45 65 45 67 65";

---

編輯：

public static void main(String [] args){ 
    String forename, surname, tempStr, InputFileName, OutputFileName, nextLine; 
    int sum = 0; 
    float average; 
    nextLine = ""; 
    tempStr = "Mildred Bush 45 65 45 67 65"; 

    String[] list = tempStr.split(" "); 
    forename = list[0]; 
    surname = list[1]; 
    int[] scores = new int[5]; 
    scores[0] = Integer.parseInt(list[2]); 
    scores[1] = Integer.parseInt(list[3]); 
    scores[2] = Integer.parseInt(list[4]); 
    scores[3] = Integer.parseInt(list[5]); 
    scores[4] = Integer.parseInt(list[6]); 
    System.out.println("Forename : "+ forename); 
    System.out.println("Surname : "+ surname); 
    System.out.print("Scores : "); 
    for(int eachInt : scores){ 
     sum+=eachInt; 
     System.out.print(eachInt+" "); 
    } 
    System.out.println(); 
    System.out.println("Average : " + sum/scores.length); 
} 

輸出：

因爲tempStr被聲明爲

Forename : Mildred 
Surname : Bush 
Scores : 45 65 45 67 65 
Average : 57