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我創建了一個數據庫（在線教程之後），它將所有用戶引導到一個登錄頁面。我想知道如何指導不同的用戶訪問不同的網頁。例如，我想將JOHN SMITH（user1）指向localhost/pages/johnsmith.html和JANE SMITH（用戶2）到localhost/pages/janesmith.html。如何在登錄後將不同的用戶導向不同的頁面？
代碼：
db_const.php
<?php
# mysql db constants DB_HOST, DB_USER, DB_PASS, DB_NAME
const DB_HOST = 'localhost';
const DB_USER = 'root';
const DB_PASS = 'root';
const DB_NAME = 'ClientDashboard';
?>
的login.php
<html>
<head>
<title>User Login Form - PHP MySQL Ligin System | W3Epic.com</title>
</head>
<body>
<h1>User Login Form - PHP MySQL Ligin System | W3Epic.com</h1>
<?php
if (!isset($_POST['submit'])){
?>
<!-- The HTML login form -->
<form action="<?=$_SERVER['PHP_SELF']?>" method="post">
Username: <input type="text" name="username" /><br />
Password: <input type="password" name="password" /><br />
<input type="submit" name="submit" value="Login" />
</form>
<?php
} else {
require_once("db_const.php");
$mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);
# check connection
if ($mysqli->connect_errno) {
echo "<p>MySQL error no {$mysqli->connect_errno} : {$mysqli->connect_error}</p>";
exit();
}
$username = $_POST['username'];
$password = $_POST['password'];
$sql = "SELECT * from users WHERE username LIKE '{$username}' AND password LIKE '{$password}' LIMIT 1";
$result = $mysqli->query($sql);
if (!$result->num_rows == 1) {
echo "<p>Invalid username/password combination</p>";
} else {
echo "<p>Logged in successfully</p>";
// do stuffs
}
}
?>
</body>
</html>
register.php
<html>
<head>
<title>User registration form- PHP MySQL Ligin System | W3Epic.com</title>
</head>
<body>
<h1>User registration form- PHP MySQL Ligin System | W3Epic.com</h1>
<?php
require_once("db_const.php");
if (!isset($_POST['submit'])) {
?> <!-- The HTML registration form -->
<form action="<?=$_SERVER['PHP_SELF']?>" method="post">
Username: <input type="text" name="username" /><br />
Password: <input type="password" name="password" /><br />
First name: <input type="text" name="first_name" /><br />
Last name: <input type="text" name="last_name" /><br />
Email: <input type="type" name="email" /><br />
<input type="submit" name="submit" value="Register" />
</form>
<?php
} else {
## connect mysql server
$mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);
# check connection
if ($mysqli->connect_errno) {
echo "<p>MySQL error no {$mysqli->connect_errno} : {$mysqli- >connect_error}</p>";
exit();
}
## query database
# prepare data for insertion
$username = $_POST['username'];
$password = $_POST['password'];
$first_name = $_POST['first_name'];
$last_name = $_POST['last_name'];
$email = $_POST['email'];
# check if username and email exist else insert
$exists = 0;
$result = $mysqli->query("SELECT username from users WHERE username = '{$username}' LIMIT 1");
if ($result->num_rows == 1) {
$exists = 1;
$result = $mysqli->query("SELECT email from users WHERE email = '{$email}' LIMIT 1");
if ($result->num_rows == 1) $exists = 2;
} else {
$result = $mysqli->query("SELECT email from users WHERE email = '{$email}' LIMIT 1");
if ($result->num_rows == 1) $exists = 3;
}
if ($exists == 1) echo "<p>Username already exists!</p>";
else if ($exists == 2) echo "<p>Username and Email already exists! </p>";
else if ($exists == 3) echo "<p>Email already exists!</p>";
else {
# insert data into mysql database
$sql = "INSERT INTO `users` (`id`, `username`, `password`, `first_name`, `last_name`, `email`)
VALUES (NULL, '{$username}', '{$password}', '{$first_name}', '{$last_name}', '{$email}')";
if ($mysqli->query($sql)) {
//echo "New Record has id ".$mysqli->insert_id;
echo "<p>Registred successfully!</p>";
} else {
echo "<p>MySQL error no {$mysqli->errno} : {$mysqli->error} </p>";
exit();
}
}
}
?>
</body>
</html>
謝謝！
我認爲這不是爲了上線，*對嗎？*最少，我當然希望不要。 –
如果JOHNS MITH創建賬戶該怎麼辦？他將擁有與JOHN SMITH相同的頁面。 – Aloso
第一個和最後一個名字永遠不會獨一無二，無法用作用戶標識符。 – Ibu