C++數組和讀取文件

Question

我正在創建一個地址簿程序，允許用戶通過名字，姓氏，電話號碼和地址進行搜索。系統會提示用戶輸入文件名，並將文件讀入數組中。我無法修改現有的SearchFirstName函數來遍歷數組。我已經多次閱讀過這個話題，我只是不理解它。任何幫助將不勝感激。

文件

Susan, Smith, 123 456 789 
101 Main Street 
Bob, Smith, 567 345 9076 
456 Market Street 

頭文件

#include<string> 
using namespace std; 

enum Title {Mr, Mrs, Ms, Dr, NA}; 

struct NameType { 
Title title; 
string firstName; 
string lastName; 
}; 

struct AddressType { 
    string street; 
    string city; 
    string state; 
    string zip; 
}; 

struct PhoneType { 
    int areaCode; 
    int prefix; 
    int number; 
}; 

    struct entryType { 
    NameType name; 
    AddressType address; 
    PhoneType phone; 
}; 

const int MAX_RECORDS = 50; 

struct addressBookType { 
    entryType record[MAX_RECORDS]; 
    int numEntries; 
}; 

代碼

string bookArray[MAX_RECORDS]; 

int main() 
{ 
    entryType userRecord; 
    string filename; 
    ifstream inData; 
    char searchOption; 

    OpenFile(filename, inData); 

    MainMenu(inData, filename); 

    return 0; 
} 

void OpenFile(string& filename, ifstream& inData) 
{ 
    do { 
     cout << "Enter file name to open: "; 
     cin >> filename; 

     inData.open(filename.c_str()); 

    if (!inData) 
     cout << "File not found!" << endl; 

} while (!inData); 


    if(inData.is_open()) 
    { 

     for(int i=0; i<MAX_RECORDS;i++) 
     { 
     inData>> bookArray[i]; 
     } 
    } 
} 

// Searches passed file stream for a first name read from the user 

void SearchFirstName(ifstream& inData) 
{ 
    string searchName; 
    entryType userRecord; 
    string normalSearchName, normalFirstName; 
    char choice; 
    bool found = false; 

    cout << "Enter first name to search for: "; 
    cin >> searchName; 

    normalSearchName = NormalizeString(searchName);  // Convert name to all uppercase 

    // Loop through all records in the file 
    while (GetRecord(inData, userRecord)){ 

    normalFirstName = NormalizeString(userRecord.name.firstName); // Convert retrieved string to all uppercase 

    if (normalFirstName == normalSearchName) { // Requested name matches 
     PrintRecord(userRecord); 
     cout << "Is this the correct entry? (Y/N)"; 
     cin >> choice; 
     choice = toupper(choice); 
     cout << endl; 

     if (choice == 'Y') { 
      found = true; 
      break; 
     } 
    } 
} 

// Matching name was found before the end of the file 
if (inData && !found){ 
    cout << "Record found: " << endl; 
    PrintRecord(userRecord); 
    cout << endl; 
} 
else if (!found) // End of file. Name not found. 
{ 
    cout << searchName << " not found!" << endl << endl; 
} 

// Clear file fail state and return to beginning 
inData.clear(); 
inData.seekg(0); 
} 

我嘗試

void SearchFirstName(ifstream& inData) 
{ 
    string searchName; 
    entryType userRecord; 


cout << "Enter first name to search for: "; 
cin >> searchName; 

string newSearchName = NormalizeString(searchName); 
string upFirst = NormalizeString(userRecord.name.firstName); 

for (int i=0;i<MAX_RECORDS;i++) 
{ 
    while(newSearchName == upFirst) 
    { 
     if (bookArray[i]== upFirst) 
     { 
      cout<<"Name Found"; 
      cout <<bookArray[i]; //test case 
     } 
    } 


} 
} 

Answer 1

1. 創建你的數組，在這種情況下，它將是一個std::vector，因爲它更簡單易用，通過在while循環中運行GetRecord函數並將結果附加到向量w/vector_variable_name.push_back(NormalizeString(value_returned_from_GetRecord));。 NormalizeString部分是你不必在數十億次後調用它。
2. 通過您的陣列中，像這樣void SearchFirstName(std::vector<entryType> *in_data_arr>)
3. 更改while循環到for循環：for (int i = 0; i < in_data_arr.size(); i++) {
4. 裏面的循環變化normalSearchName = NormalizeString(searchName);到normalSearchName = in_data_arr[i].name.firstName;

而且從那裏一般應相同。