2017-04-11 26 views
1

我已經實現了ng-file-upload指令將我的文件上傳到相應的URL .....現在當我選擇一個文件時,根據ng-file-upload的功能同時發生上傳和選擇。如何在嘗試再次上傳時使用ng-file-upload保存可見的以前上傳的文件?

但是,上傳後,當我嘗試再次上傳某些其他文件....以前上傳的文件明顯消失.....我想保留以前上傳的文件也需要得到新上傳這些文件下面...如何工作呢?

我的HTML

<form> 
     <input type="text" class="browse-form"placeholder=" Click browse to load documents " required> 
     <button ngf-select="vm.uploadFiles($files)" multiple accept=".csv,.pdf,.doc,.docx,.xlsx" class="btn btn-info btn-md">Browse</button> 
     </form> 
     <p style="margin-top: -30px;"> Note:Supported file formats are word,excel and pdf only</p> 
     <table class="table table-fixed"> 
     <thead class="table-header"><tr> 
     <th class="col-xs-6">DOCUMENT NAME</th> 
     <th class="col-xs-1">SIZE</th> 
     <th class="col-xs-1">VERSION</th> 
     <th class="col-xs-2">DATE UPLOADED</th> 
     <th class="col-xs-2">UPLOADED BY</th> 
     <th class="col-xs-1">ACTION</th></tr> 
     </thead> 
     <tbody> 
     <tr ng-repeat="uploading in vm.files track by $index" style="font:smaller"> 
     <td>{{uploading.name}}</td> 

我你爲什麼不創建一個數組,並推到它每一次文件controller.js

vm.uploadFiles = function(files){ 
vm.files = files; 
angular.forEach(files,function(file){ 
    file.upload = Upload.upload({ 
     url:' ', 
     data:{file:file} 
    }); 

    file.upload.then(function(response){ 
     $timeout(function(){ 
      file.result = response.data; 
     }); 
     }, 

    function (response) { 
     if (response.status > 0) 
      vm.errorMsg = response.status + ': ' + response.data; 
    }, 

    function (evt) { 
     file.progress = Math.min(100, parseInt(100.0 * evt.loaded/evt.total)); 
    });}); 

回答

0

上傳

vm.fileArr = [] 

vm.uploadFiles = function(files) { 


    vm.files = files; 

    angular.forEach(files, function(file) { 

     vm.fileArr.push(file)// show this array 

     file.upload = Upload.upload({ 
      url: ' ', 
      data: { 
       file: file 
      } 
     }); 
     file.upload.then(function(response) { 
       $timeout(function() { 
        file.result = response.data; 
       }); 
      }, 
      function(response) { 
       if (response.status > 0) 
        vm.errorMsg = response.status + ': ' + response.data; 
      }, 
      function(evt) { 
       file.progress = Math.min(100, parseInt(100.0 * evt.loaded/evt.total)); 
      }); 
    }); 
} 
+0

.....我顯示了這樣的內容即時通訊不能夠獲得數組內容到我的HTML ....奇怪的...它去unde罰款...:| @sachila ranawaka – HKI345

+0

保留以前上傳的文件的邏輯工作在控制器通過推到陣列....但仍然顯示爲HTML不確定...我也嘗試在foreach循環@ sachila ranawaka – HKI345

+0

你可以創建一個演示 –

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