我有兩個表sermons(sermon_id,preacher_id,sermon_name etc)
和preachers(preacher_id,firstname,lastname etc)
。現在我展示這個像第一個牧師的名字,然後是這個牧師的所有佈道等,這是正常工作。但要顯示誰擁有的佈道宣講......問題與sql查詢
下面的代碼使用,但我只拿到了1號傳道..
function viewAllpreachers($offset=0, $limit=null) {
$preacher_ids = array();
$this->db->distinct('preacher_id');
$this->db->select('preacher_id');
$this->db->from('sermons');
$query = $this->db->get();
if ($query->num_rows() > 0) {
foreach ($query->result() as $key => $res1) {
$preacher = array();
$this->db->select('*');
$this->db->from('preacher');
$this->db->where('preacher_id', $res1->preacher_id);
$this->db->order_by('first_name');
$query = $this->db->get('', $limit, $offset);
if ($query->num_rows() > 0) {
foreach ($query->result() as $row) {
$preacher[$row->preacher_id]['preacher_id'] = $row->preacher_id;
$preacher[$row->preacher_id]['preacher_name'] = $row->first_name . ' ' . $row->last_name;
$preacher[$row->preacher_id]['preacher_image'] = $row->preacher_image;
$preacher[$row->preacher_id]['preacher_bio_brief'] = $row->preacher_bio_brief;
$this->db->select('*');
$this->db->from('sermons');
$this->db->where('preacher_id', $row->preacher_id);
$this->db->order_by('sort_order ');
$sermon_array = array();
$query = $this->db->get();
if ($query->num_rows() > 0) {
foreach ($query->result() as $row1) {
$sermon_array[$row1->sermon_id] ['sermon_image'] = $row1->sermon_image;
$sermon_array[$row1->sermon_id] ['sermon_title'] = $row1->sermon_title;
$sermon_array[$row1->sermon_id] ['audio_file'] = $row1->audio_file;
$sermon_array[$row1->sermon_id] ['sermon_description'] = $row1->sermon_description;
}
}
$preacher[$row->preacher_id]['sermon'] = $sermon_array;
}
return $preacher;
}
} }
return false;
}
這豈不是簡單的內連接的情況下? – Anand 2011-12-23 09:02:46
我想顯示所有佈道者的傳教士。如果傳教士沒有semons,就不會顯示他的細節 – Natasha 2011-12-23 09:03:19
在你的代碼中,你有'return $ preacher;'這將返回並且在第一個'$ preacher'已經循環後離開函數。將所有傳道者保存在一個單獨的數組中,然後返回傳教者陣列。 – NoLifeKing 2011-12-23 09:03:23