我得到這個JSON字符串:解析到時的JSONObject沒有被正確創建(可以JSON格式錯誤?)
[
{
"id": 135,
"date": "2013-08-30 19:00:29",
"timestamp": "2013-08-30 19:00:29",
"lat": "54.328274",
"long": "-2.747215",
"strap": "annual International Festival of Street Arts",
"link": "http://dev.website.co.uk//?p=135",
"title": "Title"
}
]
這肯定是正確的JSON語法IM(在iOS應用正常工作),但是JSONObject它捕獲錯誤。 Java:
public static JSONObject getJSONfromURL(String url){
//initialize
InputStream is = null;
String result = "";
JSONObject jArray = null;
//http post
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
} catch (Exception e) {
Log.e("log_tag", "Error in http connection "+e.toString());
}
//convert response to string
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
} catch (Exception e) {
Log.e("log_tag", "Error converting result "+e.toString());
}
//try parse the string to a JSON object
try {
Log.d("log_tag", "jresult: " + result + "finish");
jArray = new JSONObject(result);
} catch (JSONException e) {
Log.e("log_tag", "Error parsing data "+e.toString());
}
return jArray;
}
JSON中某處出現錯誤嗎?
感謝
JSONArray
!這裏最好的解釋,謝謝!我會接受它,當它允許:) –@JoshBoothe歡迎您。你也可以有一個try塊,並且有很多基於異常層次的catch塊 – Raghunandan
@Raghunandan好解釋 – Blackbelt