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我有一個關於交互PHP和Linux系統的問題。從PHP運行腳本
我想從網頁推出蒸汽,而這個頁面的地址是
http://site.eu/cp/user/services/21/steaminstall
並從那裏IM運行命令
/var/www/wwwuser/data/www/site.eu/panel.php?(here goes $_POST[''] data)
和Steam客戶端是
內部路徑與網頁/var/www/wwwuser/data/Steam/SteamInstall
事情是,我知道如何訪問這個腳本,我也可以執行簡單的
echo "Script is Runing"
但是,當我的行動來驗證碼
#!/bin/bash
wget -P /var/www/aftersoft/data/Servers/Steam/ http://media.steampowered.com/client/steamcmd_linux.tar.gz &&
tar xvfz /var/www/aftersoft/data/Servers/Steam/steamcmd_linux.tar.gz -C /var/www/aftersoft/data/Servers/Steam/ &&
sh /var/www/aftersoft/data/Servers/Steam/steamcmd.sh +login anonymous +quit &&
rm /var/www/aftersoft/data/Servers/Steam/steamcmd_linux.tar.gz &&
echo "Steam Installation and Update Completed"
如果IM從網頁上運行它,它沒有做任何事情,但它工作時我嘗試SSH用戶下運行(與阿帕奇用戶有權寫入這個文件夾)
所以我的問題,我做錯了什麼?
UPDATE: 我的PHP代碼運行腳本
if($path[2] === 'steaminstall')
{
$InstallSteam = exec('/var/www/aftersoft/data/Servers/Steam/SteamInstall', $Output, $Error);
if($Error === 0)
{
$Status = $DB->SteamStatus($_SESSION['username']);
if($Status)
{
header('Location: /cp/'.$_SESSION['username'].'/services/');
}
else
{
$Smarty->assign('InstallStatus', 'Database Error Occured');
$Smarty->display('steaminstall.tpl');
}
}
if($Error === 2)
{
$Smarty->assign('InstallStatus', $Output);
$Smarty->display('steaminstall.tpl');
}
}
這是我的數據庫查詢功能
public function SteamStatus($Username)
{
$Status = '1';
$Statement = $this->DBConnection->prepare("UPDATE account set steaminstalled = ? where username = ?");
$Statement->bindParam(1, $Status);
$Statement->bindParam(2, $Username);
$IStatus = $Statement->execute();
if($IStatus)
{
return true;
}
else
{
return false;
}
}
你能提供關於你的php代碼的更多細節嗎? –
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