JSON解析數據顯示，iPhone爲同一對象的不同值

Question

當我的NSLog affecteddate值它顯示正確的，但是當我將它存儲在VAR它給出錯誤的值

SBJsonParser *parser= [[SBJsonParser alloc] init]; 

NSString *url = [NSString stringWithFormat:@"http://www.krsconnect.no/community/api.html?method=bareListEventsByCategory&appid=620&category-selected=%@&counties-selected=Vest-Agder,Aust-Agder&range=0-10", test]; 

NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:url]]; 




NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; 
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]; 
NSDictionary *object = [parser objectWithString:json_string error:nil]; 
NSArray *results = [parser objectWithString:json_string error:nil]; 
appDelegate.books1 = [[NSMutableArray alloc] init]; 
appDelegate.dates =[[NSMutableArray alloc]init]; 
appDelegate.books2=[[NSMutableArray alloc]init]; 
appDelegate.books3=[[NSMutableArray alloc]init]; 
appDelegate.books4=[[NSMutableArray alloc]init]; 
appDelegate.books5=[[NSMutableArray alloc]init]; 
appDelegate.books6=[[NSMutableArray alloc]init]; 
appDelegate.books7=[[NSMutableArray alloc]init]; 
appDelegate.books8=[[NSMutableArray alloc]init]; 
appDelegate.books9=[[NSMutableArray alloc]init]; 
appDelegate.books10=[[NSMutableArray alloc]init]; 
NSArray *activitiesArray; 

mycount=[results count]; 
for (int j=0;j<[results count]; j++) { 

    NSDictionary *dictOne = [results objectAtIndex:j]; 
    NSLog(@"%@ - %@", [dictOne objectForKey:@"date"]); 
    Date *aDate = [[Date alloc] initWithDictionary:[results objectAtIndex:j]]; 
    [appDelegate.dates addObject:aDate]; 
    [aDate release]; 
    activitiesArray = [dictOne objectForKey:@"events"]; 




    for (int i=0; i<[activitiesArray count]; i++) { 

     int testcount =[activitiesArray count]; 
     NSDictionary *dictTwo = [activitiesArray objectAtIndex:i]; 

     NSDictionary *eventDict=[dictTwo objectForKey:@"event"]; 



     // NSLog(@"%@ - %@", [dictOne objectForKey:@"date"]); 
     // NSLog(@"%@ - %@", [dictTwo objectForKey:@"affectedDate"]); 
     // NSLog(@"%@ - %@", [eventDict objectForKey:@"location"]); 



     NSInteger*date=[dictTwo objectForKey:@"affectedDate"]; 

     NSInteger*affecteddate=[dictTwo objectForKey:@"affectedDate"]; 

     NSLog(@"%@ - %@", [dictTwo objectForKey:@"affectedDate"]); 

     NSString*appId =[eventDict objectForKey:@"appId"]; 
     NSLog(@"%@ - %@", [eventDict objectForKey:@"eventId"]); 

     NSInteger*eventId=[eventDict objectForKey:@"eventId"]; 

     int next=[affecteddate intValue]; 
     int next_int = [eventId intValue]; 



     NSString*location=[eventDict objectForKey:@"location"]; 
     NSString*municipality=[eventDict objectForKey:@"municipality"]; 
     NSString*title=[eventDict objectForKey:@"title"]; 




    Book1 *aBook=[[Book1 alloc] initWithDate:date affecteddate:affecteddate eventId:eventId location:location municipality:municipality title:title]; 

第一冊類 @interface第一冊：NSObject的{ NSInteger的*日期; NSInteger * affecteddate;

 NSString *title; 
     NSString *location; 
     NSString *municipality; 


     NSInteger eventId; 

     NSString* event; 

      } 

       @property(nonatomic,readwrite) NSInteger eventId; 
       @property(nonatomic,retain) NSString* event; 
       @property(nonatomic) NSInteger *date; 

       @property(nonatomic,readwrite)NSInteger* affecteddate; 
       @property(nonatomic,retain)NSString *title; 

       @property(nonatomic,retain) NSString *location; 
       @property(nonatomic,retain) NSString *municipality; 

       -(id)initWithDate:(NSInteger *)d affecteddate:(NSInteger *)ad eventId:(NSInteger*)eId location:(NSString *)l municipality:(NSString *)m title:(NSString *)t ; 



      @end 

Answer 1

首先，你必須：

NSInteger*affecteddate=[dictTwo objectForKey:@"affectedDate"]; 

後

int next=[affecteddate intValue]; 

intValue無效的整數

你可能想：

NSNumber *date = [dictTwo objectForKey:@"affectedDate"]; 

NSNumber *affecteddate = [dictTwo objectForKey:@"affectedDate"]; 

可以聲明像這樣的書對象分配此值

NSNumber *affecteddate; 
    @propert(nonatomic,retain)