爲十六進制和正則表達式其他一些字符串

Question

我的目的是讀取一個字符串，並在不斷尋找一個整數或十六進制數，替換成「[0-9]」 我的字符串是：

a = hello word 123 with the 0x54673ef75e1a 
a1 = hello word 123 with the 0xf 
a2 = hello word 123 with the 0xea21f 
a3 = hello word 123 with the 0xfa 

試圖與以下：

b = re.sub(r"(\d+[A-Fa-f]*\d+[A-Fa-f]*)|(\d+)","[0-9]",a) 

得到下面的輸出：

hello word [0-9] with the [0-9]x[0-9]a 
hello word [0-9] with the [0-9]xf 
hello word [0-9] with the [0-9]xea[0-9] 
hello word [0-9] with the [0-9]xfa 

但outpu T應當是這樣的：

hello word [0-9] with the [0-9] 
hello word [0-9] with the [0-9] 
hello word [0-9] with the [0-9] 
hello word [0-9] with the [0-9] 

Answer 1

你的模式應該是這樣的

b = re.sub(r"(0x[a-fA-F0-9]+|\d+)","[0-9]",a) 

以十六進制和十進制值之間進行區分。

Answer 2

使用

re.sub(r"(0x[\da-fA-F]+)|(\d+)","[0-9]",a) 

參見http://ideone.com/nMMNJm