從excel導出數據到sqlite數據庫

Question

我有一個Excel表格，裏面裝滿了數據。我想在sqlite數據庫表中有相同的數據。目前我必須手動輸入1乘1字段。有什麼辦法可以將數據導出到sqlite數據庫表嗎？

Answer 1

您的路徑是通過CSV（您應該將您的數據導出爲CSV），例如在這裏查看更多。

Import CSV to SQLite

Answer 2

本網站的Excel文件轉換到sqlite的文件http://converttosqlite.com/

Answer 3

還有一個python腳本（xl2sqlite.py），將做的工作。

Answer 4

試試這個新鮮的代碼exceltosql：

''' 
This code uses the openpyxl package for playing around with excel using Python code 
to convert complete excel workbook (all sheets) to an SQLite database 
The code assumes that the first row of every sheet is the column name 
Every sheet is stored in a separate table 
The sheet name is assigned as the table name for every sheet 
''' 

import sqlite3 
import openpyxl 
from openpyxl import load_workbook 
import re 

def slugify(text, lower=1): 
    if lower == 1: 
     text = text.strip().lower() 
    text = re.sub(r'[^\w _-]+', '', text) 
    text = re.sub(r'[- ]+', '_', text) 
    return text 

#Replace with a database name 
con = sqlite3.connect('test.db') 
#replace with the complete path to youe excel workbook 
wb = load_workbook(filename=r'abc.xlsx') 

sheets = wb.get_sheet_names() 

for sheet in sheets: 
    ws = wb[sheet] 

    columns= [] 
    query = 'CREATE TABLE ' + str(slugify(sheet)) + '(ID INTEGER PRIMARY KEY AUTOINCREMENT' 
    for row in ws.rows[0]: 
     query += ', ' + slugify(row.value) + ' TEXT' 
     columns.append(slugify(row.value)) 
    query += ');' 

    con.execute(query) 

    tup = [] 
    for i, rows in enumerate(ws): 
     tuprow = [] 
     if i == 0: 
      continue 
     for row in rows: 
      tuprow.append(unicode(row.value).strip()) if unicode(row.value).strip() != 'None' else tuprow.append('') 
     tup.append(tuple(tuprow)) 


    insQuery1 = 'INSERT INTO ' + str(slugify(sheet)) + '(' 
    insQuery2 = '' 
    for col in columns: 
     insQuery1 += col + ', ' 
     insQuery2 += '?, ' 
    insQuery1 = insQuery1[:-2] + ') VALUES(' 
    insQuery2 = insQuery2[:-2] + ')' 
    insQuery = insQuery1 + insQuery2 

    con.executemany(insQuery, tup) 
    con.commit() 

con.close()