帶工作線程的線程狀態信號

Question

有人可以幫助下面的代碼。我不認爲信號正在被我的線程工作人員看到。我期望看到STEQUESIZE 1打印，但它從來沒有發生過。任何幫助，將不勝感激。

輸出爲：

開始線程 互斥鎖 做

#include <stdlib.h> 
#include <stdio.h> 
#include <signal.h> 
#include <unistd.h> 
#include <string.h> 
#include <getopt.h> 
#include <pthread.h> 

#include <errno.h> 

// GLOBALS 
pthread_mutex_t mutexqueue; 
pthread_cond_t condworker; 
pthread_t *threadIDs; 
int STEQUESIZE=0; 

void* worker(void *arg) { 
fprintf(stdout,"Thread Started\n"); 
fflush(stdout); 

    while (1) { 
    pthread_mutex_lock(&mutexqueue); 
    fprintf(stdout,"mutex locked\n"); fflush(stdout); 
    while(STEQUESIZE == 0); 
    pthread_cond_wait(&condworker, &mutexqueue); 
    fprintf(stdout,"STEQUESIZE %d\n",STEQUESIZE); 
    fflush(stdout); 
    STEQUESIZE--; 

    pthread_mutex_unlock(&mutexqueue); 
    } 
} 

int main(int argc, char **argv) { 
    int nthreads = 1; 

    STEQUESIZE=0; 
    pthread_mutex_t mutexqueue = PTHREAD_MUTEX_INITIALIZER; 
    pthread_cond_t condworker = PTHREAD_COND_INITIALIZER; 

    threadIDs = (pthread_t *)malloc(sizeof(pthread_t)*nthreads); 
    int j; 
    for(j=0; j< nthreads;j++) 
    pthread_create(&threadIDs[j], NULL, worker, NULL); 

    sleep(2); 

    pthread_mutex_lock(&mutexqueue); 
     STEQUESIZE=1; 
     pthread_cond_signal(&condworker); 
    pthread_mutex_unlock(&mutexqueue); 

    printf("done\n"); 
    while(1); 
    return 0; 
} 

Answer 1

感謝評論回答我的問題。我有全局和局部變量命名相同。

// GLOBALS 
pthread_mutex_t mutexqueue; 
pthread_cond_t condworker; 
pthread_t *threadIDs; 
int STEQUESIZE=0; 

然後

int main(int argc, char **argv) { 
    int nthreads = 1; 

    STEQUESIZE=0; 
    pthread_mutex_t mutexqueue = PTHREAD_MUTEX_INITIALIZER; 
    pthread_cond_t condworker = PTHREAD_COND_INITIALIZER;