Question

我希望任何人都可以幫我解決一個小問題。得到一個清晰的頭腦後，我仍然堅持，並找不到解決方案。我想這顯然很簡單。

我堅持一個數組結構，並需要對它們進行排序。下面是該陣列的一個小例子：

$brand["BRAND_1"]["name"] = 'Brand Name 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['name'] = 'Headline Subbrand 2'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['text'] = 'text for Subbrand 2'; 

$brand["BRAND_2"]["name"] = 'Brand Name 2'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 

可能有BRAND_N正量和n SUB_BRAND_N量。

我有一個訂單ID，其stucks一個靈活的訂單：

0 = out as in (dont worry about this, catch it at an earlier stage) 
1 = BRAND_1.SUB_BRAND_1 
2 = BRAND_1.SUB_BRAND_2 
3 = BRAND_2.SUB_BRAND_1 

此被延長，如果有更多的這四種情況以及本身可能更改順序。所以我必須使用這些ID。

順序應改變陣列中的位置和ID的值推到頂部陣列中，例如：

訂單ID = 2：

$brand["BRAND_1"]["name"] = 'Brand Name 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['name'] = 'Headline Subbrand 2'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['text'] = 'text for Subbrand 2'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 

$brand["BRAND_2"]["name"] = 'Brand Name 2'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 

順序ID = 3：

$brand["BRAND_2"]["name"] = 'Brand Name 2'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 

$brand["BRAND_1"]["name"] = 'Brand Name 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['name'] = 'Headline Subbrand 2'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['text'] = 'text for Subbrand 2'; 

---

我至今嘗試過這樣的：

<?php 

$order[1] = 'BRAND_1::SUB_BRAND_1'; 
$order[2] = 'BRAND_1::SUB_BRAND_2'; 
$order[3] = 'BRAND_2::SUB_BRAND_1'; 

// for testing 
$orderId = 2; 

// get the brand and sub_brand 
$part = explode("::", $order[$orderId]); 

// set the new brand list 
$newBrand[$part[0]]['name'] = $brand[$part[0]]['name']; 
$newBrand[$part[0]]['list'][$part[1]] = $brand[$part[0]]['list'][$part[1]]; 

// unset the brand which should be first of the main brand array 
unset($brand[$part[0]]['list'][$part[1]]); 

// if there was only one list unset the whole brand part 
if(count($brand[$part[0]]['list']) < 1) { 
    unset($brand[$part[0]]); 
} 

現在我有兩個數組：

$品牌包括整個品牌，除了這一個應該是第一

$ newBrand只包括該品牌這應該是在頂部

現在我只需要添加$品牌$ newBrand但有我的問題:) 嘗試了很多不同的方式重建數組推動內容，替換或合併... b我總是用圈子跑。

任何其他的想法，更短的代碼，更好的方法..？

我寫的整個代碼爲codepad.org更好的測試： Codepad example

讚賞任何幫助或建議。

乾杯！

編輯：

很抱歉的誤解：

順序是代碼以外的規範。目標是根據orderId將一個元素設置爲$ brand數組中的頂部。 $ orderId將通過POST，GET或類調用傳遞。

$ order數組只是一個數組，它可以幫助我在代碼中訪問規範。

所以$ orderId匹配$ order數組的一個元素，並返回這個元素，它應該位於$ brand數組的頂部。由於沒有數字鍵，我決定使用「brand :: sub_brand」語法來訪問這兩個深度級別。

希望這解釋它更好地litte。

感謝

Answer 1

這裏是一個可能的解決方案（測試here）：

<?php 

function getOrderingRules() 
{ 
    return array(
     1 => 'BRAND_1.SUB_BRAND_1', 
     2 => 'BRAND_1.SUB_BRAND_2', 
     3 => 'BRAND_2.SUB_BRAND_1', 
    ); 
} 

function getOrderedBrands($brands, $orderId) 
{ 
    $rules = getOrderingRules(); 
    if (!isset($rules[$orderId])) { 
     throw new RuntimeException("Rule for order id '$orderId' is not specified"); 
    } 

    $result = array(); 

    // Push the first element 
    list($key, $subkey) = explode('.', $rules[$orderId]); 
    $result[$key] = array(
     'name' => $brands[$key]['name'], 
     'list' => array(
      $subkey => $brands[$key]['list'][$subkey], 
     ), 
    ); 

    // Push remaining elements in the order they appear in $rules 
    foreach ($rules as $oid => $rule) { 
     // Skip order id of the first element 
     if ($oid == $orderId) { 
      continue; 
     } 
     list($key, $subkey) = explode('.', $rules[$oid]); 
     if (!isset($result[$key])) { 
      $result[$key] = array(
       'name' => $brands[$key]['name'], 
       'list' => array(), 
      ); 
     } 
     $result[$key]['list'][$subkey] = $brands[$key]['list'][$subkey]; 
    } 

    return $result; 
} 

// Loading all brands (could be external source, like database) 
$brand["BRAND_1"]["name"] = 'Brand Name 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['name'] = 'Headline Subbrand 2'; 
$brand["BRAND_1"]["list"]['SUB_BRAND_2']['text'] = 'text for Subbrand 2'; 

$brand["BRAND_2"]["name"] = 'Brand Name 2'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['name'] = 'Headline Subbrand 1'; 
$brand["BRAND_2"]["list"]['SUB_BRAND_1']['text'] = 'text for Subbrand 1'; 

// Sort and output 
print_r(getOrderedBrands($brand, 1)); 
print_r(getOrderedBrands($brand, 2)); 
print_r(getOrderedBrands($brand, 3)); 

你應該知道，這種陣列結構（$brands），您將無法設置排序規則一樣這樣的：

1 = BRAND_1.SUB_BRAND_1 
2 = BRAND_2.SUB_BRAND_1 
3 = BRAND_1.SUB_BRAND_2 

，因爲一旦你遇見元素通過BRAND_1鍵，您必須遍歷所有的它的子品牌。如果你沒有這樣的規則，一切都很好。否則，你必須存儲有序陣列結構是這樣的（因爲實際上要排序的子品牌，而不是品牌）：

$subBrands = array(
    array(
     'name' => 'Headline Subbrand 1', 
     'text' => 'Text for it', 
     'parent' => 'BRAND_1', 
     'key' => 'SUB_BRAND_1', 
    ), 
    array(
     'name' => 'Headline Subbrand 2', 
     'text' => 'Text for it', 
     'parent' => 'BRAND_1', 
     'key' => 'SUB_BRAND_2', 
    ), 
); 
$parentBrands = array(
    'BRAND_1' => 'Brand Name 1', 
    'BRAND_2' => 'Brand Name 2', 
); 

然後你就可以排序$subBrands和遍歷它