如何將文本字符串轉換爲十六進制字符串？

Question

可以說我有一個文本字符串： 「問好我的小朋友」

函數應該返回十六進制值：

5361792048656c6c6f20746f204d79204c6974746c6520467269656e64

Answer 1

莫非不能以迅速寫，但在下面的代碼的Objective-C是可能是你在找什麼：

NSString * str = @"Say Hello to My Little Friend"; 

    NSString * hexString = [NSString stringWithFormat:@"%@", 
         [NSData dataWithBytes:[str cStringUsingEncoding:NSUTF8StringEncoding] 
             length:strlen([str cStringUsingEncoding:NSUTF8StringEncoding])]]; 

    for(NSString * toRemove in [NSArray arrayWithObjects:@"<", @">", @" ", nil]) 
     hexString = [hexString stringByReplacingOccurrencesOfString:toRemove withString:@""]; 

    NSLog(@"hexStr:%@", hexString); 

上面的代碼給你給出精確的字符串：

5361792048656c6c6f20746f204d79204c6974746c6520467269656e64

希望這將有助於:)

Answer 2

你可以做到這一點像，

NSString *str = @"Say Hello to My Little Friend"; 
NSData *data = [str dataUsingEncoding:NSUTF8StringEncoding]; 

NSLog(@"data %@",data); 

Optput：data <53617920 48656c6c 6f20746f 204d7920 4c697474 6c652046 7269656e 64>

斯威夫特：

let string = "Say Hello to My Little Friend" 
let data = string.dataUsingEncoding(NSUTF8StringEncoding) 

斯威夫特3：

let string = "Say Hello to My Little Friend" 
let data = string.data(using: String.Encoding.utf8) 

Answer 3

斯威夫特4，斯威夫特3

let hex = "ABC".unicodeScalars.filter { $0.isASCII }.map { String(format: "%X", $0.value) }.joined() print(hex) // correctly yields 414243