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我有一個代碼,讀取java
中的受保護的Excel,但該代碼給我錯誤。 我的java代碼。如何在java中讀取密碼保護的.xls文件?
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.security.GeneralSecurityException;
import java.util.Iterator;
import org.apache.poi.hssf.usermodel.HSSFCell;
import org.apache.poi.hssf.usermodel.HSSFRow;
import org.apache.poi.hssf.usermodel.HSSFSheet;
import org.apache.poi.hssf.usermodel.HSSFWorkbook;
import org.apache.poi.poifs.crypt.Decryptor;
import org.apache.poi.poifs.crypt.EncryptionInfo;
import org.apache.poi.poifs.filesystem.POIFSFileSystem;
public class REadProtectedExcel {
public static void main(String[] args) {
String fname = "D:/Vijay/BRS_docs/10168/20.11.2014/20.11.2014/JCR_30.12.14_I Pay.xls";
try {
POIFSFileSystem fs = new POIFSFileSystem(new FileInputStream(fname));
EncryptionInfo info = new EncryptionInfo(fs);
Decryptor d = Decryptor.getInstance(info);
if (d.verifyPassword("vijay")) {
System.out.println("Password correct");
FileInputStream fis = new FileInputStream(fname);
HSSFWorkbook workbook = new HSSFWorkbook(fis);
HSSFSheet sheet = workbook.getSheetAt(0);
Iterator rowIter = sheet.rowIterator();
while (rowIter.hasNext()) {
HSSFRow myRow = (HSSFRow) rowIter.next();
Iterator cellIter = myRow.cellIterator();
while (cellIter.hasNext()) {
String cellvalue = "";
HSSFCell myCell = (HSSFCell) cellIter.next();
if (myCell.getCellType() == HSSFCell.CELL_TYPE_STRING) {
cellvalue = myCell.getStringCellValue();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_NUMERIC) {
cellvalue = "" + myCell.getNumericCellValue();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_BOOLEAN) {
cellvalue = "" + myCell.getBooleanCellValue();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_FORMULA) {
cellvalue = "" + myCell.getCellFormula();
} else if (myCell.getCellType() == HSSFCell.CELL_TYPE_BLANK) {
cellvalue = "";
}
System.out.println("cellvalue--" + cellvalue);
}
}
} else {
System.out.println("Password wrong");
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (GeneralSecurityException e) {
e.printStackTrace();
}
}
}
此代碼給我下面的錯誤。
java.io.FileNotFoundException: no such entry: "EncryptionInfo"
at org.apache.poi.poifs.filesystem.DirectoryNode.getEntry(DirectoryNode.java:375)
at org.apache.poi.poifs.filesystem.DirectoryNode.createDocumentInputStream(DirectoryNode.java:177)
at org.apache.poi.poifs.crypt.EncryptionInfo.<init>(EncryptionInfo.java:45)
at org.apache.poi.poifs.crypt.EncryptionInfo.<init>(EncryptionInfo.java:39)
at com.test.arrayList.REadProtectedExcel.main(REadProtectedExcel.java:22)
- 我使用poi3.9罐子,XMLBeans的-2.3.0jar,POI-ooml-3.6
- 我沒有事先得到issue.Thanks。
- 或請分享閱讀.xls文件的另一種方式。
你用xlsx試過了嗎? xls是一個很難的要求嗎? –
[密碼保護的Excel文件](http://stackoverflow.com/questions/2609301/password-protected-excel-file)的可能的重複,並尋找poi – Setu
的第二個答案,第二個答案不起作用。 – vijayk