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嗨，我發送數據時發送數據到數據庫時出現了一些問題，它說連接在數據庫中找不到數據。對於PHP新手...請幫助。將數據發送到數據庫的問題
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Login File </title>
<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/materialize/0.97.0/css/materialize.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/materialize/0.97.0/js/materialize.min.js"></script>
</head>
<body>
<script>document.write('<script src="http://' + (location.host || 'localhost').split(':')[0] + ':35729/livereload.js?snipver=1"></' + 'script>')</script>
<div class="container">
<div class="row">
<form action="login_process.php" method="post">
<legend><h1 style="color:red;">Form title </h1></legend>
<div class="input-field col s6">
<div class="form-group">
<span class="help-block"></span>
<input type="text" name="username" class="form-control" placeholder="Username">
</div>
</div>
<div class="input-field col s6">
<div class="form-group">
<span class="help-block"></span>
<input type="password" name="password" class="form-control" placeholder="Password">
</div>
</div>
<button type="submit" class="btn">Submit</button>
</form>
</div>
</div>
</body>
</html>
連接文件：
<?php
$connection = mysqli_connect('localhost', 'root', '', 'demo');
if(!$connection) {
die("Database connection failed". mysqli_error()); } else {echo "Connected";}
?>
和進程文件：
<?php
require_once 'connection.php';
if($connection) {
echo "<h1>Connected</h1>";
}
if (isset($_POST['submit'])) {
$username = $_POST['username'];
$password = $_POST['password'];
$query = "INSERT INTO user_tbl(username,password) VALUES ('$username','$password')";
$result= mysqli_query($connection,$query);
if (!$result) {
die("Query failed");
}
}
$result = mysql_query("SELECT * FROM user_tbl");
echo $result;
?>
您在數據庫中創建您的表了嗎？如果不是，你不會在上面的代碼中創建一個。你需要爲此創建表。 –
是的，我已經創建了phpmyadmin中的表，但仍然無法弄清楚什麼是錯的 –
當我提交的數據說連接，但數據不顯示在數據庫上 –