麻煩通過字符數組用C

這解析爲char數組，我想通過解析：麻煩通過字符數組用C

array1 word 2, 3, 4, 5, 6, 7

現在我已經寫了下面的代碼，試圖做到這一點：

char* variableName = strtok(currentLine, " "); // array1 

    strtok(NULL, " "); // skip the 'word' token 
    char arrayOfElements[256]; // 256 = maximum line size 

    char* currentElement = strtok(NULL, " "); // currentElement = "2," 
    strcpy(arrayOfElements, currentElement); // arrayOfElements = "2," 

    int numberOfArrayElements = 1; 

    while (currentElement != NULL) { // <== I think it's a inifinite loop becuase of this condition but I don't know how to fix this condition 
     currentElement = strtok(NULL, " "); // = "3," on first pass 
     strcat(arrayOfElements, " "); // = "3, " on first pass 
     strcat(arrayOfElements, currentElement); // arrayOfElements = "2, 3," on first pass 
     numberOfArrayElements++; 
    }

我的最終目標是我想要arrayOfElements = 2,3,4,5,6,7

來源

2013-11-21 Q Liu

如果第二個strok（）返回NULL，該怎麼辦？您正在愉快地將可能爲NULL的字符串strcpying到arrayOfElements中。實際上，在strcpy（）或strcat（）完成後，您測試它是否爲NULL。你應該先詢問，稍後再拍（訪問字符串）。 –

您是否試圖製作沒有前導''單詞''字符串的另一個字符串，或者您是否嘗試從原始字符串中創建一個整數數組？ – DevNull

最後我想arrayOfElements = 2,3,4,5,6,7 –

重新排序代碼，以便在嘗試使用指針之前進行測試。另外，需要初始化arrayOfElements。

char* variableName = strtok(currentLine, " "); // array1 

strtok(NULL, " "); // skip the 'word' token 
char arrayOfElements[256]; // 256 = maximum line size 

char* currentElement = strtok(NULL, " "); // currentElement = "2," 
int numberOfArrayElements = 0; 
arrayOfElements[0]='\0'; // initialize the array to an empty string. 

while (currentElement != NULL) { 
    if (numberOfArrayElements > 0) 
     strcat(arrayOfElements, " "); 
    strcat(arrayOfElements, currentElement); 
    numberOfArrayElements++; 
    currentElement = strtok(NULL, " "); 
}

來源

2013-11-21 17:21:20

麻煩通過字符數組用C

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